2

我刚刚用 simpletest 测试了一些 PHP 文件,发现它不适用于实际输出(回显)任何内容的函数。

那么我有什么办法可以在不使用ob_buffer()PHP 的情况下测试与内容相呼应的函数吗?

谢谢

4

2 回答 2

1

如果您正在测试输出本身的有效性,那么不会。不是没有输出缓冲区。但是,您可以使用 JavaScript 对其进行测试。您甚至可以通过将输出通过 ajax 传递回另一个线程来使用 simpletest 对其进行测试。

迂回?哦耶宝宝。

于 2010-11-17T19:20:21.767 回答
0

使用下面完全愚蠢的方法应该会给你你想要的。嘿...写起来很有趣:)

<?php
/**
 * The function which output you want to test.
 *
 * @param string $arg1
 * @param string $arg2
 */
function function_with_echo($arg1, $arg2) {
    $c = array();
    echo "X";
    foreach (range(0,2) as $i) {
        print $i * 2 . $arg2;
    }
    echo "Yir $arg1";
}

/**
 * Stupid, too big, ugly function that takes a function and creates a new
 * function with two underscores prefixed (__) where all echo and print
 * statements instead are collected into a temporary variable and returned. 
 * Does not work for functions that already returns something, although 
 * that could be fixed too!
 *
 * @param string $function_name
 */
function change_output_to_return($function_name) {
    $r = new ReflectionFunction($function_name);
    $lines = array_slice(
        file($r->getFileName()),
        $r->getStartLine() - 1,
        $r->getEndLine() - $r->getStartLine() + 1
    );
    $first = array_shift($lines);
    array_unshift($lines, $first, '$__temp = "";' . "\n");
    $last = array_pop($lines);
    array_push($lines, 'return $__temp;' . "\n", $last);
    $code = "<?php " . implode("", $lines);
    $echo_free_code = '';
    foreach(token_get_all($code) as $token) {
        if(is_array($token)) {
           if (in_array(token_name($token[0]), array('T_ECHO', 'T_PRINT'))) {
               $echo_free_code .= '$__temp .= ';
           } else {
               $echo_free_code .= $token[1];
           }
        } else {
            $echo_free_code .= $token;
        }
    }
    $echo_free_code = str_replace($function_name, "__$function_name", $echo_free_code);
    eval("?>$echo_free_code");
}

// Creates a function called "__function_with_echo" that returns a string
// instead of outputting it using "print" and "echo".
change_output_to_return('function_with_echo');

// Stuff contains the outputted data from "function_with_echo".
$stuff = __function_with_echo('fun', 'stuff');
var_dump($stuff);
于 2010-11-17T20:51:29.197 回答