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我正在使用 Mockbox 编写测试并有一个我需要测试的函数，看起来像这样

public void function placeOrder() {
  // do stuff
  local.helper = variables.injector.getInstance("orderHelper");
  local.args = { a = "hi", b = "bye" };
  try {
    invoke(local.helper, "print", local.args);  // Call 1
  }
  catch (any e) {
    local.args.tryOtherPrinter = true;
    invoke(local.helper, "print", local.args);  // Call 2
  }
  // do stuff
}

我正试图围绕如何测试placeOrder和模拟print调用，以便它第一次而不是第二次抛出异常。我认为，关键是每次传入的参数都会不同，但如果我不确定它们，它就不会正确映射到我的模拟并且不会抛出异常。

到目前为止，这是我的测试代码：

// local.order and local.helper are mocks
local.printArgs = { a = "hi", b = "bye" };
local.printArgs2 = { a = "hi", b = "bye", tryOtherPrinter = true };
// should you be able to do this and it'll throw based on the args...
local.helper.$(method = "print", throwException = true).$args(local.printArgs).$results("");
// ... and not throw based on the other args?
local.helper.$(method = "print").$args(local.printArgs2).$results("");
local.order.placeOrder();
assertEquals(2, local.helper.$count("print"), "Expected print to be called twice");

我在文档中知道你可以让它在后续调用中返回不同的结果，但在这种情况下，我需要它抛出，然后不抛出，看起来当你模拟一个方法时，它对于你是否在问是相当确定的它扔还是不扔。

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