我在 web.xml 中为我的网络服务添加了一个健康链接
<filter>
<filter-name>healthChecker</filter-name>
<filter-class>test.HealthChecker</filter-class>
</filter>
<filter-mapping>
<filter-name>healthChecker</filter-name>
<url-pattern>/health</url-pattern>
</filter-mapping>
<filter>
<filter-name>basicAuthenticationFilter</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
<async-supported>true</async-supported><!-- filter supports asynchronous processing -->
</filter>
<filter-mapping>
<filter-name>basicAuthenticationFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
现在我想对这个健康检查进行单元测试
@Test
public void testHealthCheck() {
ClientHttpRequestFactory originalRequestFactory = restTemplate.getRequestFactory();
try {
WebTarget target = target().path("/health");;
final Response mockResponse = target.request().get();
Assert.assertNotNull("Response must not be null", mockResponse.getEntity());
} finally {
restTemplate.setRequestFactory(originalRequestFactory);
}
}
健康检查器的代码是
public class HealthChecker implements Filter {
@Override
public void destroy() {
//do nothing
}
@Override
public void doFilter(ServletRequest request, ServletResponse response,
FilterChain chain) throws IOException, ServletException {
response.setContentType("text/json");
String json ="{\"status\":\"UP\"}";
response.getWriter().append(json);
}
@Override
public void init(FilterConfig filter) throws ServletException {
// do nothing
}
}
现在,当我执行此单元测试时,我收到 404 错误。如果我看到目标,那么目标中的 url 是http://localhost:9998/health,这是正确的。
我在 chrome 中使用了这个 url,但什么也得不到。
这是在球衣测试框架中完成的