time1 = "2010-04-20 10:07:30"
time2 = "2010-04-21 10:07:30"
如何将上述内容从字符串转换为时间戳?
我需要减去上面的时间戳time2-time1
。
对于 Python 2.5+
from datetime import datetime
format = '%Y-%m-%d %H:%M:%S'
print datetime.strptime(time2, format) -
datetime.strptime(time1, format)
# 1 day, 0:00:00
编辑:对于 Python 2.4
import time
format = '%Y-%m-%d %H:%M:%S'
print time.mktime(time.strptime(time2, format)) -
time.mktime(time.strptime(time1, format))
# 86400.0
>>> t1 = datetime.strptime(time1, "%Y-%m-%d %H:%M:%S")
>>> t2 = datetime.strptime(time2, "%Y-%m-%d %H:%M:%S")
>>> t2-t1
datetime.timedelta(1)
>>> (t2-t1).days
1
>>> (t2-t1).seconds
0
如果你像我一样被困在 Python 2.4 系统上:
from time import strptime
from datetime import datetime
str_to_datetime = lambda st: datetime(*strptime(st, '%Y-%m-%d %H:%M:%S')[:6])
str_to_datetime('2010-04-20 10:07:30')
否则 datetime.strptime() 会正常工作。
import time
time1 = "2010-04-20 10:07:30"
time_tuple = time.strptime(time1, "%Y-%m-%d %H:%M:%S")
timestamp = time.mktime(time_tuple)