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我试图将用户非规范化回一个完整的对象。我正在尝试根据此处的文档进行操作。据我了解，输入应该是结果值之一，然后您提供架构和实体来处理重建对象。但是，返回的值是一个具有 0 键和输入值的对象。{0:44}例如，而不是整个非规范化的用户对象。

userSchemas.js

import { schema } from 'normalizr';

const photos = new schema.Entity('photos')
const phones = new schema.Entity('phones')
const user = new schema.Entity('users', {
    photos: [photos],
    phones: [phones]
})

const usersSchema = new schema.Array(users)

export { usersSchema, user as userSchema }

非规范化

denormalize([user], userSchema, this.props.users.entities)

this.props.users.entities

{
users : { 
         1: {id:1, name: "john", phones:[2]}
        },
photos : {},
phones : {
          2: {id:2, phone: "34234324"}
         }
}

编辑：可以粘贴到http://requirebin.com的要点，在控制台中显示问题

var normalizr = require("normalizr")

const photos = new normalizr.schema.Entity('photos')
const phones = new normalizr.schema.Entity('phones')
const user = new normalizr.schema.Entity('user', {
    photos: [photos],
    phones: [phones]
})

const usersSchema = new normalizr.schema.Array(user)

var users = [
  {id: 1, name: "bob", phones: [{id:3, phone: 45234324},{id:4, phone: 42342432}]},
    {id: 2, name: "will", phones: [{id:3, phone: 45234324},{id:6, phone: 5435345}]},
    {id: 4, name: "sam", phones: [{id:6, phone: 5345353},{id:7, phone: 42342432}]}
]

var normalizedUsers = normalizr.normalize(users, usersSchema)

var denormalizedUser = normalizr.denormalize([2], user, normalizedUsers)

console.log(denormalizedUser)
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1 回答 1

3

这一行是错误的：

var denormalizedUser = normalizr.denormalize([2], user, normalizedUsers)

您的第一个论点应该只是，2或者您的第二个论点应该是[ user ].

[编辑]

此外，normalizedUsers应该只是entities，而不是完整的标准化结果。采用normalizedUsers.entities

于 2017-01-26T23:30:29.737 回答