5

我需要将带有 dom4j 的 xml 构建转换为 w3c 文档,并且不知道如何做...

4

3 回答 3

9

查看 DOMWriter。这对我有用:

import org.dom4j.DocumentHelper;    
import org.dom4j.io.DOMWriter;

org.dom4j.Document dom4jDoc = DocumentHelper.createDocument();    
org.w3c.dom.Document w3cDoc = new DOMWriter().write(dom4jDoc)
于 2012-04-20T19:23:33.180 回答
6

我假设你想从:

org.dom4j.Document

到:

org.w3c.dom.Document

dom4j 快速入门指南

Document document = ...;
String text = document.asXML();

从String to Document的JavaRanch 示例:

public static Document stringToDom(String xmlSource) 
        throws SAXException, ParserConfigurationException, IOException {
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    DocumentBuilder builder = factory.newDocumentBuilder();
    return builder.parse(new InputSource(new StringReader(xmlSource)));
}

结合2,你应该有你需要的东西。

于 2010-11-15T03:31:39.870 回答
6

如果您有大型文档,出于性能原因,您可能希望避免将文档序列化为文本。在这种情况下,最好直接使用 SAX 事件进行转换:

private static final TransformerFactory transformerFactory =
                                           TransformerFactory.newInstance();

public static org.w3c.dom.Document toW3c(org.dom4j.Document dom4jdoc)
         throws TransformerException {

    SAXSource source = new DocumentSource(dom4jdoc);
    DOMResult result = new DOMResult(); 

    Transformer transformer = transformerFactory.newTransformer(); 

    transformer.transform(source, result);
    return (org.w3c.dom.Document) result.getNode();
}
于 2010-11-15T09:52:11.223 回答