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I am writing a program for school that reduces noise in a sound file. So far i have written this code which I think takes n number of samples before a set one and n after and then averages the two. My problem is that everytime my second for loop runs i get a sampleoutofboundexception. I am guessing this means that it cant find the sample that i am asking it to look for, but i dont understand why.

for (int s = 0; s<= aSound.getNumSamples(); s++){    

  for ( int i=0; i<=level ; i++ ) {
    nSamp = aSound.getSample(i);
    sSize = nSamp.getValue();
    total=total + sSize;
  }

  for (int j = 0; j >= -level; j--){
    sSize2 = aSound.getSample(j).getValue();
    total1 = total1 + sSize2;
  }
  avg = (total1 + total) / level*2;

  for (int i = 0; i <= level*2+1; i++){
    result.getSample(i).setValue(avg);
  }
 }
 return aSound;
  }

I get the error every single time this line is run and I can't understand why. any help? thank you

sSize2 = aSound.getSample(j).getValue();
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2 回答 2

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的价值是level多少？我假设它是积极的，在这种情况下

for (int j = 0; j >= -level; j--)

在 的负值上循环j，负索引通常是无效的。这就是为什么你得到一个索引越界异常。

如果这不能解决您的问题，您应该发布更多详细信息，例如对象aSound的类型。

于 2010-11-13T03:11:46.327 回答
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aSound 是一个包含 55125 个样本的 wav 文件的对象

aSound 就是收藏。它没有我评论中写的负指数

我认为 aSound 是一个集合，数组或集合没有负索引

于 2010-11-13T03:39:15.983 回答