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我有以下文件（@Document）：

@Id
private String id;
private String fileName;
private String projectId;
private List<DocumentFileVersion> documentFileVersions;
private List<String> userIdBlackList; // here userIds are included

这是我目前的聚合：

final String userId = "5589929b887dc1fdb501cdbb";
final Aggregation aggregate = newAggregation(match(Criteria.where("projectId").in(projectId)),
        group("fileName").count().as("amountOfDocumentFiles"));
    final AggregationResults<DocumentFileAmount> groupDocumentFiles = mongoTemplate.aggregate(aggregate, DocumentFile.class,
        DocumentFileAmount.class);
    final List<DocumentFileAmount> documentFileAmounts = groupDocumentFiles.getMappedResults();
    final int amountOfDocumentFiles = documentFileAmounts.size();

现在，我将以这种方式扩展聚合，即只有在 userId（在本例中为“1234”）不在userIdBlackList中的 DocumentFiles 中。有没有可能这样做，比如在伪代码中：

final Aggregation aggregate = newAggregation(match(Criteria.where("projectId").in(projectId).and(userId).notInList("userIdBlackList")),
    group("fileName").count().as("amountOfDocumentFiles"));

我需要这样的东西：... .and(userId).notInList("userIdBlackList") ...

[编辑] 我试过这个查询：

final Aggregation aggregate = newAggregation(
        match(Criteria.where("projectId").in(projectId).and(userId).and("‌​userIdBlackList").ne(userId)),
        group("fileName").count().as("amountOfDocumentFiles"));

数据库条目可能如下所示：

{
"_id" : ObjectId("587e7cabafdaff28743f3034"),
"_class" : "com.smartinnotec.legalprojectmanagement.dao.domain.DocumentFile",
"fileName" : "Hydrangeas.jpg",
"projectId" : "587e7c95afdaff28743f302e",
"userIdBlackList" : [
    "5589929b887dc1fdb501cdbb"
    ]
}

但是.and(userId).and("‌​userIdBlackList").ne(userId)没有效果。

[编辑2]

我也尝试在 mongo 控制台中模拟它。我已经使用命令db.DocumentFile.find().pretty()列出了所有文档文件：

db.DocumentFile.find().pretty()
{
"_id" : ObjectId("587f0d61473c92b933a68efa"),
"_class" :   "com.smartinnotec.legalprojectmanagement.dao.domain.DocumentFile",
"fileName" : "DocumentFile1",
"ending" : "jpg",
"projectId" : "587f0d61473c92b933a68ef9",
"active" : true,
"userIdBlackList" : [
    "587f0d61473c92b933a68ef8"
]}

我的查询如下所示：

db.DocumentFile.aggregate({ "$match" : { "projectId" : { "$in" : [ "587f0d61473c92b933a68ef9"]} , "‌​userIdBlackList" : { "$ne" : "587f0d61473c92b933a68ef8"}}}).pretty();
{
"_id" : ObjectId("587f0d61473c92b933a68efa"),
"_class" : "com.smartinnotec.legalprojectmanagement.dao.domain.DocumentFile",
"fileName" : "DocumentFile1",
"ending" : "jpg",
"projectId" : "587f0d61473c92b933a68ef9",
"active" : true,
"userIdBlackList" : [
    "587f0d61473c92b933a68ef8"
]}

我原以为我没有得到文档文件，因为这个表达式"‌​userIdBlackList" : { "$ne" : "587f0d61473c92b933a68ef8"} 有人知道我做错了什么吗？

[编辑3]

我有这两个文件和aggegate：

final Aggregation aggregate = newAggregation(
            match(Criteria.where("projectId").in(projectId).and("‌​userIdBlackList").nin(userId)),
            group("fileName").count().as("amountOfDocumentFiles"));

我得到了 2 的数量，但应该是 1。我不知道我做错了什么？

db.DocumentFile.find().pretty()
{
"_id" : ObjectId("587f2228e232342f74b166f9"),
"_class" : "com.smartinnotec.legalprojectmanagement.dao.domain.DocumentFile",
"fileName" : "DocumentFile1",
"ending" : "jpg",
"projectId" : "587f2228e232342f74b166f8",
"active" : true,
"userIdBlackList" : [
    "587f2228e232342f74b166f7"
]}
{
"_id" : ObjectId("587f2228e232342f74b166fa"),
"_class" : "com.smartinnotec.legalprojectmanagement.dao.domain.DocumentFile",
"fileName" : "DocumentFile2",
"ending" : "jpg",
"projectId" : "587f2228e232342f74b166f8",
"active" : true,
"userIdBlackList" : [ ]
}
4

1 回答 1

0

您是否尝试过使用.nin

final Aggregation aggregate = newAggregation(
                match(Criteria.where("projectId").in(projectId).and("‌​userIdBlackList").nin(userId)),
                group("fileName").count().as("amountOfDocumentFiles"));
于 2017-01-18T07:48:23.493 回答