8

我创建了一个独立的应用程序,我希望当用户单击运行按钮时终端应该打开并且应该在终端上执行特定的命令。我可以使用以下代码成功打开终端...

Process process = null;  
try {  
    process = new ProcessBuilder("xterm").start();  
} catch (IOException ex) {  
    System.err.println(ex);  
}  

上面的代码打开了一个终端窗口,但我无法对其执行任何命令。谁能告诉我该怎么做?

4

3 回答 3

5

尝试

new ProcessBuilder("xterm", "-e", 
                   "/full/path/to/your/program").start()
于 2010-11-12T12:08:58.403 回答
4

在 linux 中按原样执行任何命令,就像您在终端中键入的内容一样:

    import java.io.BufferedReader;
    import java.io.IOException;
    import java.io.InputStreamReader;

    public class CommandExecutor {
    public static String execute(String command){
        StringBuilder sb = new StringBuilder();
        String[] commands = new String[]{"/bin/sh","-c", command};
        try {
            Process proc = new ProcessBuilder(commands).start();
            BufferedReader stdInput = new BufferedReader(new 
                    InputStreamReader(proc.getInputStream()));

            BufferedReader stdError = new BufferedReader(new 
                    InputStreamReader(proc.getErrorStream()));

            String s = null;
            while ((s = stdInput.readLine()) != null) {
                sb.append(s);
                sb.append("\n");
            }

            while ((s = stdError.readLine()) != null) {
                sb.append(s);
                sb.append("\n");
            }
        } catch (IOException e) {
            e.printStackTrace();
        }
        return sb.toString();
    }

}

用法:

CommandExecutor.execute("ps ax | grep postgres");

或复杂如:

CommandExecutor.execute("echo 'hello world' | openssl rsautl -encrypt -inkey public.pem -pubin | openssl enc -base64");

String command = "ssh user@database-dev 'pg_dump -U postgres -w -h localhost db1 --schema-only'";
CommandExecutor.execute(command);
于 2013-03-05T11:20:32.123 回答
2

假设您正在尝试您的 gedit 命令,那么您需要提供 gedit 的完整路径(例如 /usr/bin/gedit)。同样为所有其他命令指定完整路径。

于 2010-11-17T12:05:43.957 回答