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我有一个要求，我必须使用以下每月数据为每个员工生成报告。该报告在每个月的第一天运行，并提供截至上个月第一天的数据。要求是将这些数据划分为每周数据。因此，如果每个月的第一天从“星期一”开始，则一周应该有 5 个工作日，“星期二”有 4 个工作日，“星期三”有 3 个工作日等等。并根据员工工作的天数计​​算工作时间对应的一周。如果每个月的周数都不同，那么报告应该相应地显示每周的数据。

EmpName Date        WorkTime
User1   2016-10-18  NULL
User1   2016-10-20  06:00:38
User1   2016-10-21  07:41:44
User1   2016-10-24  06:35:53
User1   2016-10-25  06:29:03
User1   2016-10-26  07:25:09
User1   2016-10-31  07:49:12
User1   2016-11-03  09:23:05
User1   2016-11-05  NULL
User1   2016-11-07  09:18:38
User1   2016-11-08  09:16:01
User1   2016-11-09  08:05:03
User1   2016-11-11  09:00:43
User1   2016-11-16  09:18:14

以下是上述查询的预期结果。

WeekNum WeekDur         EmpName Planned     Actual
Week1   18/10 - 22/10   User1   32:00:00    13:42:22
Week2   23/10 - 29/10   User1   40:00:00    20:30:05
Week3   30/10 - 31/10   User1   8:00:00     7:49:12

注意：计划小时数是根据工作日数计算的。表示周一至周五，因此每天 8 小时将提供 40 小时，每周工作 5 天。但是，需要计算所有 7 天的实际时间，以便如果有人在周末工作，那么实际时间可以相应地反映任何超出计划时间的时间。

注意：NULL 表示员工没有正确刷入/刷出。

抱歉，我自己没有尝试过任何事情，因为我对这种要求不熟悉，并且在处理日期和时间查询方面经验很少。

我希望我已经提供了所有信息，并要求所有人在有任何问题或困惑时与我联系。

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1 回答 1

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我认为您实际上不能拥有time超过 24 小时的数据类型，因此我将您的工作时间分解为单独的字段，以便您做自己想做的事情。您可以cte通过将大日期case语句添加到您的 中来取消group by，但这意味着重复的代码，因此需要重复更新它的工作，我很懒惰：

declare @t table (EmpName nvarchar(10), WorkDate date, WorkTime time);
insert into @t values
 ('User1','20161018',NULL),('User1','20161020','06:00:38'),('User1','20161021','07:41:44'),('User1','20161024','06:35:53'),('User1','20161025','06:29:03'),('User1','20161026','07:25:09'),('User1','20161031','07:49:12'),('User1','20161103','09:23:05'),('User1','20161105',NULL),('User1','20161107','09:18:38'),('User1','20161108','09:16:01'),('User1','20161109','08:05:03'),('User1','20161111','09:00:43'),('User1','20161116','09:18:14');

with cte as
(
select EmpName
            -- Pick the later of either the start of the current week or the current month.
        ,case when dateadd(wk, datediff(wk,0,WorkDate), 0) < dateadd(month,datediff(month,0,WorkDate),0)
                then dateadd(month,datediff(month,0,WorkDate),0)    -- This calculates the start of the month.
                else dateadd(wk, datediff(wk,0,WorkDate), 0)        -- This calculated the start of the week.
                end as WeekStart

            -- Pick the earlier of either the end of the current week or the current month.
        ,case when dateadd(d,6,dateadd(wk, datediff(wk,0,WorkDate), 0)) >= dateadd(month,datediff(month,0,WorkDate)+1,0)
                then dateadd(d,-1,dateadd(month,datediff(month,0,WorkDate)+1,0))    -- This calculates the last day of the month.
                else dateadd(d,6,dateadd(wk, datediff(wk,0,WorkDate), 0))           -- This calculates the last day of the week.
                end as WeekEnd

            -- Pick the earlier of either the friday of the current week or or the end of the current month.
        ,case when dateadd(d,4,dateadd(wk, datediff(wk,0,WorkDate), 0)) > case when dateadd(d,6,dateadd(wk, datediff(wk,0,WorkDate), 0)) >= dateadd(month,datediff(month,0,WorkDate)+1,0)
                                                                                then dateadd(d,-1,dateadd(month,datediff(month,0,WorkDate)+1,0))    -- This calculates the last day of the month.
                                                                                else dateadd(d,6,dateadd(wk, datediff(wk,0,WorkDate), 0))           -- This calculates the last day of the week.
                                                                                end

                then case when dateadd(d,6,dateadd(wk, datediff(wk,0,WorkDate), 0)) >= dateadd(month,datediff(month,0,WorkDate)+1,0)
                            then dateadd(d,-1,dateadd(month,datediff(month,0,WorkDate)+1,0))    -- This calculates the last day of the month.
                            else dateadd(d,6,dateadd(wk, datediff(wk,0,WorkDate), 0))           -- This calculates the last day of the week.
                            end
                else dateadd(d,4,dateadd(wk, datediff(wk,0,WorkDate), 0))           -- This calculates the Friday of the week.
                end as WorkingWeekEnd

        ,datepart(hour,WorkTime) as HoursWorked
        ,datepart(minute,WorkTime) as MinutesWorked
        ,datepart(second,WorkTime) as SecondsWorked
from @t
)
select EmpName
        ,WeekStart
        ,WeekEnd
        ,WorkingWeekEnd
        ,avg(datediff(d,WeekStart,WorkingWeekEnd)+1) * 8 as PlannedHoursWorked
        ,isnull(sum(HoursWorked),0) as HoursWorked
        ,isnull(sum(MinutesWorked),0) as MinutesWorked
        ,isnull(sum(SecondsWorked),0) as SecondsWorked
from cte
group by EmpName
        ,WeekStart
        ,WeekEnd
        ,WorkingWeekEnd
order by EmpName
        ,WeekStart;

输出：

╔═════════╦═════════════════════════╦═════════════════════════╦═════════════════════════╦════════════════════╦═════════════╦═══════════════╦═══════════════╗
║ EmpName ║        WeekStart        ║         WeekEnd         ║     WorkingWeekEnd      ║ PlannedHoursWorked ║ HoursWorked ║ MinutesWorked ║ SecondsWorked ║
╠═════════╬═════════════════════════╬═════════════════════════╬═════════════════════════╬════════════════════╬═════════════╬═══════════════╬═══════════════╣
║ User1   ║ 2016-10-17 00:00:00.000 ║ 2016-10-23 00:00:00.000 ║ 2016-10-21 00:00:00.000 ║                 40 ║          13 ║            41 ║            82 ║
║ User1   ║ 2016-10-24 00:00:00.000 ║ 2016-10-30 00:00:00.000 ║ 2016-10-28 00:00:00.000 ║                 40 ║          19 ║            89 ║            65 ║
║ User1   ║ 2016-10-31 00:00:00.000 ║ 2016-10-31 00:00:00.000 ║ 2016-10-31 00:00:00.000 ║                  8 ║           7 ║            49 ║            12 ║
║ User1   ║ 2016-11-01 00:00:00.000 ║ 2016-11-06 00:00:00.000 ║ 2016-11-04 00:00:00.000 ║                 32 ║           9 ║            23 ║             5 ║
║ User1   ║ 2016-11-07 00:00:00.000 ║ 2016-11-13 00:00:00.000 ║ 2016-11-11 00:00:00.000 ║                 40 ║          35 ║            39 ║            85 ║
║ User1   ║ 2016-11-14 00:00:00.000 ║ 2016-11-20 00:00:00.000 ║ 2016-11-18 00:00:00.000 ║                 40 ║           9 ║            18 ║            14 ║
╚═════════╩═════════════════════════╩═════════════════════════╩═════════════════════════╩════════════════════╩═════════════╩═══════════════╩═══════════════╝
于 2017-01-13T12:45:19.397 回答