groovy - 如何解析 URL 以在 groovy 中获取其参数？

Question

我是 groovy 脚本的新手，正在寻找解析 URL 并打印它的参数。

这个网址是：https ://www.google.com/?aaa=111&bbb=222&ccc=33& dd =1484088989_b23f248ac6e5d9a9b47475526bb92ee1

如何从 URL中获取dd参数？

我感谢您的帮助！

Answer 1

您需要添加一个 groovy 脚本。

def groovyUtils = new com.eviware.soapui.support.GroovyUtils( context );
def testCase = context.testCase;
def testStep = testCase.getTestStepByName("NAME_TESTStepRequest");  
def endpoint =testStep.getPropertyValue('Endpoint');
log.info endpoint;
def url = new URL(endpoint)
//def url = new URL("https://www.google.com/?aaa=111&bbb=222&ccc=33&dd=1484088989_b23f248ac6e5d9a9b47475526bb92ee1")

// get all query params as list
def queryParams = url.query?.split('&') // safe operator for urls without query params
// transform the params list to a Map spliting 
// each query param
def mapParams = queryParams.collectEntries { param -> param.split('=').collect { URLDecoder.decode(it) }}
// assert the expected values
log.info mapParams['aaa']
//assert mapParams['aaa'] == '111'
log.info mapParams['bbb']
//assert mapParams['bbb']== 'abc'
log.info mapParams['dd']
//assert mapParams['dd']=='023423'

请你检查这个帖子。使用 groovy 从请求 url soapui 获取查询参数