嵌套的内部事务已提交的数据更改实际上应该在父事务中立即可见。
而且我真的不知道为什么它们不在. 其他人也不知道,并且正在使用类似的方法来挖掘.GroovyTestCase
考虑以下测试用例。测试用例本身不是事务性的,而是调用事务性方法。- 这按预期工作。
class TransactionalMethodTest extends GroovyTestCase {
static transactional = false // test case is not transactional
def customerService
void testTransactionsCommit() {
// start a new transaction,
// setting order 1 inactive
setOrderInactive()
assert ! Order.get(1).isActive
}
@Transactional(propagation = Propagation.REQUIRED)
private void setOrderInactive() {
// make sure that order 1 is active
Order order = Order.get(1)
order.isActive = true
order.save(flush:true)
assert Order.get(1).isActive
// the following method acts in isolation level
// Propagation.REQUIRES_NEW, which means,
// a new, nested, transaction is started
// >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
customerService.cancelOrders([1])
// changes from the nested transaction are
// visible, instantly
assert ! Order.get(1).isActive
// <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
}
}
现在考虑以下“正常”事务性测试用例。嵌套事务中的数据更改在父事务中不可见。
我只能说,事务性测试用例不适用于嵌套事务,因此请使用上面的非事务性测试用例。
如果我们不了解原因,我们至少可以知道我们的选择。
class TransactionalTestCaseTests extends GroovyTestCase {
static transactional = true // default; Propagation.REQUIRED
def customerService
void testTransactionsCommit() {
// make sure that order 1 is active
Order order = Order.get(1)
order.isActive = true
order.save(flush:true)
assert Order.get(1).isActive
// the following method acts in isolation level
// Propagation.REQUIRES_NEW, which means,
// a new, nested, transaction is started
// >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
customerService.cancelOrders([1])
// the changes from the inner transaction
// are not yet visible
assert Order.get(1).isActive
// <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
}
@Override
protected void tearDown() throws Exception {
// the changes from the inner transaction
// are still not visible
assert Order.get(1).isActive
super.tearDown();
}
}
与您的主要问题无关,但与您的总体意图无关,这是一个测试用例,用于检查嵌套事务是否正确回滚:
class NestedTransactionRolledBackTests extends GroovyTestCase {
static transactional = false // test case is not transactional
def customerService
void testTransactionsCommit() {
// start a new transaction,
// setting order 1 active
setOrderActive()
assert Order.get(1).isActive
}
@Transactional(propagation = Propagation.REQUIRED)
private void setOrderActive() {
// make sure that order 1 is active
Order order = Order.get(1)
order.isActive = true
order.save(flush:true)
assert Order.get(1).isActive
// the following method acts in isolation level
// Propagation.REQUIRES_NEW, which means,
// a new, nested, transaction is started.
// This transaction will fail, and be rolled back.
// >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
shouldFail(NullPointerException) {
customerService.cancelOrders([1, -999])
}
// changes from the nested transaction are
// visible, instantly.
// The changes have been rolled back
assert Order.get(1).isActive
// <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<
}
}
最后,一些更一般的旁注,它不是boolean transactional = true
(虽然它似乎有效),但是static transactional = true
. 您的集成测试也应该extend
GroovyTestCase
,而不是它的子类GrailsUnitTestCase
,因为您不需要后者的模拟功能。该isActive
字段应命名active
为 then,isActive()
将按照命名约定自动生成一个 getter。