我刚刚让我的第一个关系数据库模式/查询/解析器在 apollo/postgres/sequelize 中工作,直到解析器将数据返回给客户端的时候。显然我还没有正确形状的数据,因为它在客户端上显示为空。
询问
const CREATE_APPT_MUTATION = gql`
mutation createAPPT ($originatingUserID: String!, $apptWithUserID: String!, $apptDateTime: String!, $apptNotes: String!, $apptTitle: String!){
createAPPT(originatingUserID: $originatingUserID, apptWithUserID: $apptWithUserID, apptDateTime: $apptDateTime, apptNotes: $apptNotes, apptTitle: $apptTitle){
originatingUserID
apptWithUserID
apptDateTime
apptNotes
apptTitle
}
}
`;
解析器的当前响应形状
通过在服务器上运行的 console.log,在发送到客户端之前:
{ data:
{ __typename: 'Mutation',
createAPPT:
{ id: '76',
originatingUserID: 'DsmkoaYPeAumREsqC',
apptWithUserID: '9W95z8A7Y6i34buk7',
apptDateTime: '2016-12-24T02:48:50.000Z',
apptTitle: 'Appointment with Benedict Sama',
apptNotes: 'asdf',
createdAt: Fri Dec 23 2016 10:49:12 GMT-0800 (PST),
updatedAt: Fri Dec 23 2016 10:49:12 GMT-0800 (PST),
UserData: [Object],
__typename: 'Appts'
}
}
}
当它返回给客户端时,它在 Chrome 开发工具中的外观
mutationResult: Object
data: Object
createAPPT: Object
__typename: "Appts"
apptDateTime: null
apptNotes: null
apptTitle: null
apptWithUserID: null
originatingUserID: null
__proto__: Object
__proto__: Object
__proto__: Object
解析器中的最后THEN
一块
.then(apptWithJoinedData => {
//package up the results in the way that the client is expecting
const apptDataValues = apptWithJoinedData[0].dataValues;
apptDataValues.__typename = "Appts";
var serverResponse = {};
serverResponse.data = {};
serverResponse.data.__typename = 'Mutation';
serverResponse.data.createAPPT = apptDataValues;
// publish subscription notification
debugger;
console.log(serverResponse);
pubsub.publish('APPTAdded', serverResponse);
return serverResponse;
})
有人可以指点我看看服务器响应的形状有什么问题吗?