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我正在尝试从表中获取记录总数并使用以下 MySQL 查询：

SELECT COUNT(*) AS cnt FROM `info` WHERE 1 GROUP BY FROM_UNIXTIME(signup_date, '%Y-%m-%d') ORDER BY signup_date DESC

但它导致以下错误：

SQL 错误（1055）：ORDER BY 子句的表达式 #1 不在 GROUP BY 子句中，并且包含在功能上不依赖于 GROUP BY 子句中的列的非聚合列“rentown.info.signup_date”；这与 sql_mode=only_full_group_by 不兼容。[SELECT COUNT( ) AS cnt FROM infoWHERE 1 GROUP BY FROM_UNIXTIME(signup_date, '%Y-%m-%d') ORDER BY signup_date DESC]

这是我的表格格式：

+ Options
    id  email   signup_date     ip  city_name   firstname   address     state   lastname    city    zipcode     phonenumber     current_url     creditscore
    4   kfct@yahoo.com  1388525440  108.200.78.136  Philadelphia, PA    Kathy   1915 Apex Ave #1/4  California  Yeung   Los Angeles     90039   310 890 3338    NULL    NULL
    10  mlh@gmail.com   1388884727  98.199.141.66   Dickinson, TX   Mackenzie   102 strand  Texas   Helms   Galveston   77550   409 599 8024    NULL    NULL
    11  mjma@yahoo.com  1388889053  99.190.210.155  Grand Prairie, TX   samathiis   1701 towne crossing blvd #731   Texas   ashley  mansfield   76063   817 210     NULL    NULL
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2 回答 2

3

错误消息是不言自明的。您只能按出现在GROUP BY子句或聚合中的列进行排序。为了快速修复，只需按照分组时使用的相同术语进行排序。

SELECT COUNT(*) AS cnt
FROM `info`
GROUP BY FROM_UNIXTIME(signup_date, '%Y-%m-%d')
ORDER BY FROM_UNIXTIME(signup_date, '%Y-%m-%d') DESC
于 2016-12-19T12:34:59.837 回答
0

对于记录总数，这应该足够了：

SELECT COUNT (*) AS cnt
FROM 'info'
ORDER BY signup_date DESC
于 2016-12-19T12:37:05.797 回答