2

我有一个查询返回错误，超出了最大递归级别。

我知道如何通过添加OPTION (maxrecursion 0)到查询来解决这个问题，但是，我尝试在查询中的各个位置添加它，但我找不到将它放在语法有效的位置。

任何人都可以给我任何关于我认为需要在哪里插入查询提示的指示吗？

/****** Object:  View [dbo].[SiconCFMContractLinesDetailByDayView]    Script Date: 16/12/2016 12:02:35 ******/
SET ANSI_NULLS ON
GO

SET QUOTED_IDENTIFIER ON
GO

CREATE VIEW [dbo].[SiconCFMContractLinesDetailByDayView]
AS
WITH dateRange as
(
SELECT      [Date] = DATEADD(dd, 1, DATEADD(dd, -1,[SiconCFMContractLinesOutstandingView].[NextDueDate])),
[Frequency] = [SiconCFMContractLinesOutstandingView].[FrequencyValue],
[EndDate] = DATEADD(yy,5, [SiconCFMContractLinesOutstandingView].[NextDueDate]),
[SiconCFMContractLinesOutstandingView].[SiconContractLineID]
FROM        [SiconCFMContractLinesOutstandingView]
WHERE       DATEADD(mm, [SiconCFMContractLinesOutstandingView].[FrequencyValue], [SiconCFMContractLinesOutstandingView].[NextDueDate]) < DATEADD(mm, [SiconCFMContractLinesOutstandingView].[FrequencyValue], DATEADD(yy,5, [SiconCFMContractLinesOutstandingView].[NextDueDate]))
UNION ALL
SELECT      DATEADD(mm, [Frequency], [Date]) [Date],
[Frequency],
[EndDate],
[SiconContractLineID]
FROM        dateRange
WHERE       DATEADD(mm, [Frequency], [Date]) < DATEADD(mm, [Frequency],[EndDate])

)

SELECT
(
SELECT CASE
WHEN dbo.fnSiconCFMGetSettingValue('UseAverageTimeToPay') = 'True'
THEN
CASE [SiconCFMSLCustomerAverageTimeToPayView].[AvgTimeToPayDateLastUpdated]
WHEN NULL THEN dbo.fnSiconCFMDateByPaymentTerms([SLCustomerAccount].[SYSPaymentTermsBasisID], [SLCustomerAccount].[PaymentTermsInDays], dateRange.[Date])
ELSE DATEADD([DD],[SiconCFMSLCustomerAverageTimeToPayView].[Days],dateRange.[Date])
END
ELSE dbo.fnSiconCFMDateByPaymentTerms([SLCustomerAccount].[SYSPaymentTermsBasisID], [SLCustomerAccount].[PaymentTermsInDays], dateRange.[Date])
END
)
AS [DueDate],
[StockItem].[Name] AS [Title],
[SiconCFMContractLinesOutstandingView].[Description] AS [Description],
[SiconCFMContractLinesOutstandingView].[UnitBillCoverPriceIncDisc] AS [Value],
[SiconCFMContractLinesOutstandingView].[SiconContractID],
[SiconCFMContractLinesOutstandingView].[SiconContractLineID],
[SiconCFMContractLinesOutstandingView].[SiconContractLineID] AS [ForecastDateForeignID],
'SiconContractLine' AS [ForecastDateSource],
(
SELECT
CASE WHEN EXISTS
(
SELECT [SiconCFMMemo].[SiconCFMMemoID]
FROM   [SiconCFMMemo]
WHERE  [SiconCFMMemo].[Deleted]=0
AND    [SiconCFMMemo].[IsActive]=1
AND    [SiconCFMMemo].[MemoSource]='SiconContractLine'
AND    [SiconCFMMemo].[MemoForeignID]=[SiconCFMContractLinesOutstandingView].[SiconContractLineID]
)
THEN 1
ELSE 0
END
) AS [HasMemos]
FROM            dateRange 
INNER JOIN      [SiconCFMContractLinesOutstandingView]
ON              dateRange.[SiconContractLineID]
=               [SiconCFMContractLinesOutstandingView].[siconContractLineID]
INNER JOIN      [StockItem]
ON              [StockItem].[ItemID]
=               [SiconCFMContractLinesOutstandingView].[ItemID]
INNER JOIN      [SLCustomerAccount]
ON              [SLCustomerAccount].[SLCustomerAccountID]
=               [SiconCFMContractLinesOutstandingView].[SLCustomerAccountID]
INNER JOIN      [SiconCFMSLCustomerAverageTimeToPayView]
ON              [SiconCFMSLCustomerAverageTimeToPayView].[SLCustomerAccountID]
=               [SLCustomerAccount].[SLCustomerAccountID]
GO

正如建议的那样，我已将OPTION (maxrecursion 0)添加到最后一个 GO 语句的正上方，但是在创建视图语句中时，它会给出语法错误。如果我自己运行查询，则在创建视图语句之外它可以工作

4

2 回答 2

5

通常，在使用递归 cte 的 select 语句的末尾。
但是，在视图中不起作用。快速搜索让我找到了这篇文章- 这解释了正确的方法。

事实证明，您不能在视图中使用查询提示，但您可以并且应该在调用视图的查询中使用它。

样品表：

CREATE TABLE T
(
    id int,
    parent int
)
INSERT INTO T VALUES (1, NULL), (2, 1), (3, 1), (4, 2), (5, 2), (6, 3), (7, 4), (8, 5);
GO

创建视图：

CREATE VIEW V
AS

WITH CTE AS
(
    SELECT id, parent
    FROM T 
    WHERE parent IS NULL
    UNION ALL

    SELECT t.id, t.parent
    FROM T
    INNER JOIN CTE ON t.parent = cte.id
)

SELECT *
FROM CTE

GO

执行视图：

SELECT *
FROM V
OPTION (MAXRECURSION 2);
于 2016-12-16T11:59:27.350 回答
0

有一个非常好的脚本，我用Ann Lewkowicz 递归地检查外键

但是，我曾经有一个数据库，它有很多约束，包括一些表中的外键约束。

在运行上面的脚本时，出现以下错误：

声明终止。在语句完成之前，最大递归 32767 已用尽。

然后我使用限制了脚本的输出，top一切都很好

 select top 100 *
 from   recurseWithFields 
--OPTION (MAXRECURSION 32767);
于 2019-09-23T16:42:03.793 回答