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假设我有 3 个表（如下所示）。

series_no表：

|   id  |  desc_seriesno  |
|:------|----------------:|
| 7040  |     AU1011      |
| 7041  |     AU1022      |
| 7042  |     AU1033      |
| 7043  |     AU1044      |
| 7044  |     AU1055      |
| 7045  |     AU1066      |

品牌表：

|   id  |  desc_brand     |
|:------|----------------:|
| 1020  |     Audi        |
| 1021  |     Bentley     |
| 1022  |     Ford        |
| 1023  |     BMW         |
| 1024  |     Mazda       |
| 1025  |     Toyota      |

car_info表：

|   seriesno_id  |  brand_id  |  color  |
|:---------------|------------|--------:|
|     7040       |    1020    | white   |
|     7040       |    1020    | black   |
|     7040       |    1020    | pink    |
|     7041       |    1021    | yellow  |
|     7041       |    1021    | brown   |
|     7042       |    1022    | purple  |
|     7042       |    1022    | black   |
|     7042       |    1022    | green   |
|     7043       |    1023    | blue    |
|     7044       |    1024    | red     |
|     7045       |    1025    | maroon  |
|     7045       |    1025    | white   |

我如何分组或组合相似/相同的字符串，而不用在连接字符串中更改它们，而只是覆盖相同的字符串。

这是我当前对 sql server 2014 的查询：-

SELECT SN.id AS seriesid, B.id AS brandid, B.desc_brand
FROM [db1].[dbo].[series_no] SN
  LEFT JOIN [db1].[dbo].[car_info] CI
  ON CI.seriesno_id = SN.id
  RIGHT JOIN [db1].[dbo].[brand] B
  ON B.id = CI.brand_id
GROUP BY SN.id, B.id, B.desc_brand
ORDER BY SN.id ASC

但不幸的是，它给了我一个错误，因为我不能以这种方式按类似的字符串分组。

我希望它是这样的：-

|  seriesid  |   brandid  |   desc_brand  |
|:-----------|------------|--------------:|
|    7040    |    1020    |     Audi      |
|    7041    |    1021    |     Bentley   |
|    7042    |    1022    |     Ford      |
|    7043    |    1023    |     BMW       |
|    7044    |    1024    |     Mazda     |
|    7045    |    1025    |     Toyota    |

而不是这个（连接字符串）： -

|  seriesid  |   brandid  |       desc_brand      |
|:-----------|------------|----------------------:|
|    7040    |    1020    |     Audi, Audi, Audi  |
|    7041    |    1021    |     Bentley, Bentley  |
|    7042    |    1022    |     Ford, Ford, Ford  |
|    7043    |    1023    |     BMW               |
|    7044    |    1024    |     Mazda             |
|    7045    |    1025    |     Toyota, Toyota    |
4

1 回答 1

0

只需您需要避免重复，因此请使用以下两种方法之一：

通过...分组

select col1, col2 .. 
from table1 a inner join table2 b
on ..
group by col1, col2 ..

清楚的

 select distinct col1, col2 .. 
    from table1 a inner join table2 b
    on ..

演示：-

Create database TestDB
go
use TestDB
go
Create table series_no (id int ,desc_seriesno varchar(20) )
go
insert into series_no values (7040, 'AU1011'),
                        (7041, 'AU1022'),
                        (7042, 'AU1033'),
                        (7043, 'AU1044'),
                        (7044, 'AU1055'),
                        (7045, 'AU1066')
go
Create table brand (id int ,desc_brand varchar(20) )
go
insert into brand values (1020, 'Audi'),
                        (1021, 'Bentley'),
                        (1022, 'Ford'),
                        (1023, 'BMW'),
                        (1024, 'Mazda'),
                        (1025, 'Toyota')

Create table car_info (seriesno_id int ,brand_id varchar(20), color varchar (20) )
go
insert into car_info values(7040,1020,'white'),
(7040,1020,'black'),
(7040,1020,'pink'),
(7041,1021,'yellow'),
(7041,1021,'brown'),
(7042,1022,'purple'),
(7042,1022,'black'),
(7042,1022,'green'),
(7043,1023,'blue'),
(7044,1024,'red'),
(7045,1025,'maroon'),
(7045,1025,'white')
go

select a.seriesno_id as seriesnoid, a.brand_id as brandid,b.desc_brand
from car_info a inner join brand b
on brand_id = id
group by a.seriesno_id , a.brand_id ,b.desc_brand

/*
-- Or
select distinct a.seriesno_id as seriesnoid, a.brand_id as brandid,b.desc_brand
from car_info a inner join brand b
on brand_id = id
*/

结果：-

在此处输入图像描述

于 2016-12-15T07:59:43.253 回答