1

我NSMutableURLRequest正在向 PHP 发送两次字符串。我究竟做错了什么？

- (void)viewDidLoad {

// Printando os Dados

/////

NSString *endereco = [[NSString alloc] initWithFormat:@"%@ - CEP: %@", self.sharedData.dataEndereco, self.sharedData.dataCEP];


NSMutableURLRequest *request = 
[[NSMutableURLRequest alloc] initWithURL:
 [NSURL URLWithString:@"http://localhost/dev/mcomm/pedido.php"]];
NSLog(@"ENVI");

[request setHTTPMethod:@"POST"];
NSString *postString = [[NSString alloc] initWithFormat:@"nome=%@&email=%@&endereco=%@&produto=%@&marca=%@&preco=%@&codigo=%@&variacao=%@&parcelas=%@&valorParcelas=%@&cartao=%@&numCartao=%@&codCartao=%@&vencCartao=%@&nomeCartao=%@", self.sharedData.dataNome, self.sharedData.dataEmail, endereco, self.sharedData.dataProd, self.sharedData.dataMarca, self.sharedData.dataPreco, self.sharedData.dataCodigo, self.sharedData.dataVariacao, self.sharedData.numParcelas, self.sharedData.valorParcelas, self.sharedData.cartao, self.sharedData.numeroCartao, self.sharedData.codigoCartao, self.sharedData.dataVencimento, self.sharedData.nomeImpressoCartao];

[request setValue:[NSString 
                   stringWithFormat:@"%d", [postString length]] 
 forHTTPHeaderField:@"Content-length"];

[request setHTTPBody:[postString 
                      dataUsingEncoding:NSUTF8StringEncoding]];

[[NSURLConnection alloc] 
 initWithRequest:request delegate:self];

[UIApplication sharedApplication].networkActivityIndicatorVisible = YES;
[loaderAtividade startAnimating];


//get response
NSHTTPURLResponse* urlResponse = nil;  
NSError *error = [[NSError alloc] init];  
NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error];  
NSString *result = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
4

3 回答 3

3

第一个请求由以下发起：

[[NSURLConnection alloc] initWithRequest:request delegate:self];

第二个是由函数发送的：

 [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&error];

苹果文档中关于 sendSynchronous 的警告：

重要提示：由于此调用可能需要几分钟才能失败（尤其是在 iOS 中使用蜂窝网络时），因此您永远不应从 GUI 应用程序的主线程调用此函数。

您应该实现 NSURLConnection 委托协议并避免发送同步请求。

于 2011-10-08T23:07:43.597 回答
0 
NSURLConnection *conn = .....
if(conn){
    ......

    [conn cancel];//! important!
    [conn release];
}

停止连接

于 2012-08-18T09:28:14.670 回答
0

除了丹尼尔的回答，您可以通过实施 initWithRequest:delegate:startImmediately: with NO 来防止第一个请求触发

NSURLConnection *urlConnection = [[NSURLConnection alloc] initWithRequest:request delegate:self startImmediately:NO];

稍后，当您想启动异步请求时，只需在连接对象上调用 -start

[urlConnection start];
于 2011-10-08T23:38:10.577 回答