azure - 通过 ARM 模板创建 Azure blob/fileshare 容器

Question

我正在寻找一种通过 ARM 模板在 Azure blob 和文件共享存储中创建容器的方法。

目前我有 ARM 模板来配置存储帐户，但我也想在 ARM 中创建容器。

{
    "name": "[parameters('storageAccountName')]",
    "type": "Microsoft.Storage/storageAccounts",
    "location": "[resourceGroup().location]",
    "apiVersion": "[variables('storageApiVersion')]",
    "sku": {
        "name": "[variables('storageAccountType')]"
    },
    "dependsOn": [ ],
    "tags": {
      "Environment": "[parameters('Environment')]",
      "Project": "[parameters('ProjectName')]",
      "Contact": "[parameters('ContactName')]"
    },
    "kind": "Storage",
    "properties": {
      "encryption": {
        "keySource": "Microsoft.Storage",
        "services": {
              "blob": {
                "enabled": true
              }
        }
      }
    }
  }

Answer 1

It is possible. Azure Management REST Api now has endpoints for Blob Containers: https://docs.microsoft.com/en-us/rest/api/storagerp/blobcontainers/create.

Since ARM Templates map to REST requests, we can create the following Template, containing a Blob Container as a nested resource below the Storage Account. Of course, you can also describe the Blob container in the toplevel resource array, following the usual rules.

{
  "$schema": "http://schema.management.azure.com/schemas/2014-04-01-preview/deploymentTemplate.json#",
  "contentVersion": "1.0.0.0",
  "parameters": {},
  "variables": {
    "accountName": "accountname",
    "containerName": "containername"
  },
  "resources": [
    {
      "type": "Microsoft.Storage/storageAccounts",
      "name": "[variables('accountName')]",
      "apiVersion": "2018-02-01",
      "location": "westeurope",
      "kind": "BlobStorage",
      "sku": {
        "name": "Standard_LRS",
        "tier": "Standard"
      },
      "tags": {},
      "dependsOn": [],
      "properties": {
        "accessTier": "Cool"
      },
      "resources": [
        {
          "type": "blobServices/containers",
          "apiVersion": "2018-03-01-preview",
          "name": "[concat('default/', variables('containerName'))]",
          "dependsOn": [
            "[variables('accountName')]"
          ],
          "properties": {
            "publicAccess": "None"
          }
        }
      ]
    }
  ]
}

Answer 2

不，您不能这样做，请参阅此反馈项。

您现在可以创建容器。https://stackoverflow.com/a/51608344/6067741