我想绘制包含栅格和矢量数据的缩放对象。目前,我正在绘制一个缩放的 Graphics2D 对象
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g.create();
//Get transformation, apply scale and shifts
at = g2d.getTransform();
at.translate(x, y);
at.scale(zoom, zoom);
//Transform Graphics2D object
g2d.setTransform(at);
//Draw buffered image into the transformed object
g2d.drawImage(img, 0, 0, this);
//Draw line into transformed Graphics2D object
Line2D.Double line = new Line2D.Double();
line.x1 = (int)p1.getX();
line.y1 = (int)p1.getY();
line.x2 = (int)p2.getX();
line.y2 = (int)p2.getY();
g2d.draw(line);
g2d.dispose();
}
不幸的是,这种方法有一些缺点(影响笔画宽度,缩放图像的质量较差)。
相反,我想绘制缩放的对象。对于矢量数据,方法很简单:
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g.create();
//Update affine transformation
at = AffineTransform.getTranslateInstance(x, y);
at = AffineTransform.getScaleInstance(zoom, zoom);
//Transform line and draw
Line2D.Double line = new Line2D.Double();
line.x1 = (int)p1.getX();
line.y1 = (int)p1.getY();
line.x2 = (int)p2.getX();
line.y2 = (int)p2.getY();
g2d.draw(at.createTransformedShape((Shape)line));
//Transform buffered image and draw ???
g2d.draw(at.createTransformedShape((Shape)img)); //Error
g2d.dispose();
}
但是,如何在不重新缩放 Graphics2D 对象的情况下将转换应用于缓冲图像?这种方法不起作用
g2d.draw(at.createTransformedShape((Shape)img));
因为光栅图像不能理解为矢量形状......
谢谢你的帮助。