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我有一个dict类型的对象列表，这些对象Case以dict. 在 Python2 中运行时，我可以遍历键和值，以方便我使用该six库的两个 Python 版本。

class Case:

    def __init__(self, obj):

        properties = {}
        # standardize Boolean properties
        true_values = ['1', 1, True, 'yes', 'Yes', 'YES']
        false_values = ['0', 0, False, 'no', 'No', 'NO']
        for (k, v) in iteritems(properties):
            # standardize TRUE values
            if v in true_values:
                properties[k] = True
            # standardize FALSE values
            elif v in false_values:
                properties[k] = False
            # keep String values
            elif isinstance(v, str):
                continue

        # remove NULL values
        filtered = {k: v for (k, v) in iteritems(properties) if v != None}

        # set Case instance attribute for each property
        for (k, v) in iteritems(filtered):
            setattr(self, k, v)

    def __iter__(self):
        return self

    def __getitem__(self, key):
        return self.__dict__.get(key, None)

    def to_json(self):
        return json.dumps(self, default=lambda o: o.__dict__)

当我遍历这个列表时，尽管遵循了six 文档，但我得到了一个 AttributeError 。

我遍历上述对象的列表：

from six import iteritems

def transform(case_list):
    for case in case_list:
        for (key, value) in iteritems(case): #crashes here
            #do stuff

但是每次都会得到一个 AttributeError ：

Traceback (most recent call last):
File "app/run.py", line 134, in <module>
main()
File "/home/user/other.py", line 55, in transform
for (key, value) in iteritems(case):
File "/home/user/env/lib/python3.4/site-packages/six-1.10.0-py3.4.egg/six.py", line 581, in iteritems
return iter(d.items(**kw))
AttributeError: 'Case' object has no attribute 'items'

我用python3 app/run.py. 为什么它不识别可迭代对象？

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1 回答 1

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items()我通过向Case 类添加方法找到了解决方案：

    def items(self):
        return zip(self.__dict__.values(), self.__dict__.keys())
于 2016-12-01T19:46:47.923 回答