4

我需要在java中用空格分隔单词，所以我使用.split了函数来实现如下所示

String keyword = "apple mango ";
String keywords [] = keyword .split(" ");

上面的代码工作正常，但唯一的是我的关键字有时会包含关键字，如"jackfruit"、"ice cream"和双引号，如下所示

String keyword = "apple mango \"jack fruit\" \"ice cream\"";

在这种情况下，我需要在关键字数组中获取 4 个单词，例如apple , mango , jackfruit , ice cream

谁能告诉我一些解决方案

4

5 回答 5

4 
List<String> parts = new ArrayList<>();
String keyword = "apple mango \"jack fruit\" \"ice cream\"";

// first use a matcher to grab the quoted terms
Pattern p = Pattern.compile("\"(.*?)\"");      
Matcher m = p.matcher(keyword);
while (m.find()) {
    parts.add(m.group(1));
}

// then remove all quoted terms (quotes included)
keyword = keyword.replaceAll("\".*?\"", "")
                 .trim();

// finally split the remaining keywords on whitespace
if (keyword.replaceAll("\\s", "").length() > 0) {
    Collections.addAll(parts, keyword.split("\\s+"));
}

for (String part : parts) {
    System.out.println(part);
}

输出：

jack fruit
ice cream
apple
mango
于 2016-12-01T14:32:11.377 回答
3

我会用一个正则表达式和两个捕获组来做，每个模式一个。我不知道任何其他方式。

    String keyword = "apple mango \"jack fruit\" \"ice cream\"";
    Pattern p = Pattern.compile("\"?(\\w+\\W+\\w+)\"|(\\w+)");      
    Matcher m = p.matcher(keyword);
    while (m.find()) {
        String word = m.group(1) == null ? m.group(2) : m.group(1);
        System.out.println(word);
    }
于 2016-12-01T14:22:12.757 回答
0

这将在引号上分割字符串，然后用空格另外分割成员。

    String keyword = "apple mango \"jack fruit\" \"ice cream\"";
    String splitQuotes [] = keyword.split("\"");

    List<String> keywords = new ArrayList<>();

    for (int i = 0; i < splitQuotes.length; i++) {
        if (i % 2 == 0) {
            Collections.addAll(keywords, splitQuotes[i].split(" "));
        } else {
            keywords.add(splitQuotes[i]);
        }
    }
于 2016-12-01T14:24:16.010 回答
0

该解决方案有效，但我确信这不是性能/资源的最佳选择。当你有两个以上单词的水果时，它也有效。随意编辑或优化我的代码。

public static void main(String[] args) {
        String keyword = "apple mango \"jack fruit\" \"ice cream\" \"one two three\"";
        String[] split = custom_split(keyword);
        for (String s : split) {
            System.out.println(s);
        }
    }

    private static String[] custom_split(String keyword) {
        String[] split = keyword.split(" ");
        ArrayList<String> list = new ArrayList<>();
        StringBuilder temp = new StringBuilder();
        boolean multiple = false;
        for (String s : split) {
            if (s.startsWith("\"")) {
                multiple = true;
                s = s.replaceAll("\"", "");
                temp.append(s);
                continue;
            }
            if (s.endsWith("\"")) {
                multiple = false;
                s = s.replaceAll("\"", "");
                temp.append(" ").append(s);
                list.add(temp.toString());
                temp = new StringBuilder();
                continue;
            }
            if (multiple) {
                temp.append(" ").append(s);
            } else {
                list.add(s);
            }
        }
        String[] result = new String[list.size()];
        for (int i = 0; i < list.size(); i++) {
            result[i] = list.get(i);
        }
        return result;
    }
于 2016-12-01T14:15:49.907 回答
0

你不能用String.split(). 您需要为目标标记提供一个正则表达式，并通过匹配器收集它们，如下所示：

    final Pattern token = Pattern.compile( "[^\"\\s]+|\"[^\"]*\"" );

    List<String> tokens = new ArrayList<>();
    Matcher m = token.matcher( "apple mango \"jack fruit\" \"ice cream\"" );
    while( m.find() )
        tokens.add( m.group() );
于 2016-12-01T14:21:05.473 回答