1

VC++ 编译器警告C4250的含义对我来说很清楚。（但请参阅此处以获取解释。） 'class1' : inherits 'class2::member' via dominance

我目前遇到的问题是在序列化具有带有 boost::serialization (1.44.0)的抽象基类的类层次结构时收到此警告。

请注意，我的类 没有形成任何可能导致此警告的菱形继承层次结构，但该警告是由boost::detail::is_virtual_base_of_impl<...>序列化派生类实例时的实例化引起的。（这似乎是使用来自 Boost.TypeTraits 的is_virtual_base_of 。）

这是在 Visual Studio 2005 上重现警告的最小代码示例。请注意，代码应按原样放置到一个 cpp 文件中，并且应该可以编译。

还要注意代码中我用触发警告的注释标记的两点。如果BOOST_CLASS_EXPORT未使用，则不会触发警告，但更有趣的是，如果派生类不使用继承，也不会触发警告！（所以也许我毕竟不了解C4250。）virtual

// -- std includes --
#include <iostream>
#include <sstream>
#include <string>

// -- boost serialization --
#define BOOST_SERIALIZATION_DYN_LINK
#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>
#include <boost/serialization/export.hpp>

// Base with serialization support
struct Base
{
  virtual ~Base() {};
  virtual void DoStuff() const {
    std::cout << "Base@[" << static_cast<const void*>(this) << "]::DoStuff() called\n";
  }

  template<class Archive> // serialization support!
  void serialize(Archive & ar, const unsigned int file_version)  { /*empty*/  }
};

// (The only) Specific class with ser. support
struct Concrete2 : virtual/*!C4250!*/ public Base
{
  virtual void DoStuff() const {
    std::cout << "Concrete2@[" << static_cast<const void*>(this) << "]::DoStuff() called\n";
  }

  template<class Archive> // serialization support!
  void serialize(Archive & ar, const unsigned int ver) {
    ar & boost::serialization::base_object<Base>(*this);
    // This is just a test - no members neccessary
    std::cout << "Concrete2::serialize!" << typeid(ar).name() << "\n";
  }
};
// Without guid export -> *no* C4250, even *with* virtual inheritance
// (however, can't be serialized via base class pointer anymore)
BOOST_CLASS_EXPORT(Concrete2); 

BOOST_CLASS_TRACKING(Concrete2, boost::serialization::track_never);

int main() {
  using namespace std;
  Concrete2 obj1;
  obj1.DoStuff();

  // The following test code is not neccessary to generate the warning ...
  // (but is neccessary to show if base-pointer serialization works at runtime)
  Base* ref1 = &obj1;
  ostringstream out_buf;
  boost::archive::text_oarchive out_archive(out_buf);
  out_archive << ref1;
  const string buf = out_buf.str();

  cout << "Serialized obj:\n~~~~\n";
  cout << buf;
  cout << "\n~~~~~\n";

  std::istringstream in_buf(buf);
  boost::archive::text_iarchive in_archive(in_buf);
  // Concrete2 obj2;
  Base* ref2;
  in_archive >> ref2;
  if(ref2)
    ref2->DoStuff();
  delete ref2;
}

这是编译器警告（啊！）：

1>...\boost_library-1_44_0\boost\type_traits\is_virtual_base_of.hpp(61) : warning C4250: 'boost::detail::is_virtual_base_of_impl<Base,Derived,tag>::X' : inherits 'Concrete2::Concrete2::DoStuff' via dominance
1>        with
1>        [
1>            Base=type,
1>            Derived=Concrete2,
1>            tag=boost::mpl::bool_<true>
1>        ]
1>        ...\boostserializewarningtest\vbc.cpp(27) : see declaration of 'Concrete2::DoStuff'
...
1>        ...\boost_library-1_44_0\boost\mpl\eval_if.hpp(40) : see reference to class template instantiation 'boost::mpl::if_<T1,T2,T3>' being compiled
1>        with
1>        [
1>            T1=boost::is_virtual_base_of<type,Concrete2>,
1>            T2=boost::mpl::identity<boost::serialization::void_cast_detail::void_caster_virtual_base<Concrete2,type>>,
1>            T3=boost::mpl::identity<boost::serialization::void_cast_detail::void_caster_primitive<Concrete2,type>>
1>        ]
1>        ...\boost_library-1_44_0\boost\serialization\void_cast.hpp(279) : see reference to class template instantiation 'boost::mpl::eval_if<C,F1,F2>' being compiled
1>        with
1>        [
1>            C=boost::is_virtual_base_of<type,Concrete2>,
1>            F1=boost::mpl::identity<boost::serialization::void_cast_detail::void_caster_virtual_base<Concrete2,type>>,
1>            F2=boost::mpl::identity<boost::serialization::void_cast_detail::void_caster_primitive<Concrete2,type>>
1>        ]
1>        ...\boost_library-1_44_0\boost\serialization\base_object.hpp(68) : see reference to function template instantiation 'const boost::serialization::void_cast_detail::void_caster &boost::serialization::void_cast_register<Derived,Base>(const Derived *,const Base *)' being compiled
1>        with
1>        [
1>            Derived=Concrete2,
1>            Base=type
1>        ]
...    
1>        ...\boost_library-1_44_0\boost\serialization\export.hpp(128) : while compiling class template member function 'void boost::archive::detail::`anonymous-namespace'::guid_initializer<T>::export_guid(boost::mpl::false_) const'
1>        with
1>        [
1>            T=Concrete2
1>        ]
1>        ...\boostserializewarningtest\vbc.cpp(40) : see reference to class template instantiation 'boost::archive::detail::`anonymous-namespace'::guid_initializer<T>' being compiled
1>        with
1>        [
1>            T=Concrete2
1>        ]
4

1 回答 1

1

原因实际上是is_virtual_base_of来自提升类型特征的检查。如果检查成功，此检查构造将生成警告 C4250，如下例所示：

...
struct base { 
    virtual void mf() { };
};
struct derived_normal : public base { 
    virtual void mf() { };
};
struct derived_virt : virtual public base { 
    virtual void mf() { };
};

int main() {
    using namespace std;

    cout << "boost::is_virtual_base_of<base, derived_normal>::value reports: ";
    // The following line DOES NOT cause C4250
    cout << boost::is_virtual_base_of<base, derived_normal>::value << endl;

    cout << "boost::is_virtual_base_of<base, derived_virt> reports: ";
    // The following line causes C4250:
    cout << boost::is_virtual_base_of<base, derived_virt>::value << endl;
 ...

FWIW，这种类型特征工具在 boost 序列化中的使用是这样的：

  • 宏BOOST_EXPORT_CLASS->
    • 宏BOOST_CLASS_EXPORT_IMPLEMENT->
      • struct guid_initializer（在 export.hpp 中）->
      • (...) void_cast.hpp / void_cast_register-> is_virtual_base_of 在这里使用

据我所知，在这种情况下，警告是完全无害的，可以通过将标头包装起来来防止：

#pragma warning( push )
#pragma warning( disable : 4250 ) // C4250 - 'class1' : inherits 'class2::member' via dominance
#include ...
#pragma warning( pop ) // C4250
于 2010-11-05T07:44:23.227 回答