1

我被卡住了（有点），我似乎看不到完成这段代码的方法。我必须设计一个没有数组的程序（我的老师很糟糕，不允许数组-_-）该程序的目标是输入 3-5 个单词，并按字母顺序排列。我制作了一个可以使用 3 个单词的程序，但对如何制作一个按字母顺序排列 5 个单词的程序感到困惑。任何帮助，将不胜感激。请注意，我的问题与其他按字母顺序排列的无数组问题不同，因为它涉及 5 个单词，而不是 3、2 或任何其他数量。谢谢您的帮助！代码如下。

import java.util.Scanner;
public class Alphabetize
{    int nums = 1;
    int x = 0;
    String input01 = "";
    String input02 = "";
    String input03 = "";
    String input04 = "";
    String input05 = "";
    int compare01, compare02, compare03, compare04, compare05;
    public static void main(String[] args)
    {
        Alphabetize a = new Alphabetize();
        a.getInput();
        a.comparer();
    }

    public void getInput()
    {
        Scanner kb = new Scanner(System.in);
        System.out.println("How many words do you want to input");
        nums = kb.nextInt();

        System.out.println("Enter " + nums +" words");
            if(nums == 3)
            {
                input01 = kb.next();
                input02 = kb.next();
                input03 = kb.next();
            }

            else if(nums == 4)
            {
                input01 = kb.next();
                input02 = kb.next();
                input03 = kb.next();
                input04 = kb.next();
            }
            else
            {
                input01 = kb.next();
                input02 = kb.next();
                input03 = kb.next();
                input04 = kb.next();
                input05 = kb.next();
            }

    }

    public void comparer()
    {
        if (nums ==3)
        {        
            compare01 = input01.compareTo(input01);
                System.out.println(input01 + compare01);

            compare02 = input01.compareTo(input02);
                System.out.println(input02 + compare02);

            compare03 = input01.compareTo(input03);
                System.out.println(input03 + compare03);
        }

        else if (nums ==4)
        {

            compare01 = input01.compareTo(input01);
                System.out.println(input01 + compare01);

            compare02 = input01.compareTo(input02);
                System.out.println(input02 + compare02);

            compare03 = input01.compareTo(input03);
                System.out.println(input03 + compare03);

            compare04 = input01.compareTo(input04);
                System.out.println(input04 + compare04);
        }

        else
        {        
            compare01 = input01.compareTo(input01);
                System.out.println(input01 + compare01);

            compare02 = input01.compareTo(input02);
                System.out.println(input02 + compare02);

            compare03 = input01.compareTo(input03);
                System.out.println(input03 + compare03);

            compare04 = input01.compareTo(input04);
                System.out.println(input04 + compare04);

            compare05 = input01.compareTo(input05);
                System.out.println(input05 + compare05);
        }
    }

   }
4

0 回答 0