1

我在 LinqPad 4 中尝试了以下测试并得到了“Observable not in context”错误。IEnumerable 分支可以工作,而且奇怪的是,我没有得到 IObservable 本身的错误,只是静态方法 Observable.Range。

static void Main()
{
 IEnumerableSieve();
 IObservableSieve();
}

private static void IEnumerableSieve()
{
 IEnumerable<int> oddsFrom3 = IntsFrom(3, 2);
 List<int> cache = new List<int>() { 2 };

 IEnumerable<int> primes = oddsFrom3.
  Where(candidate => cache.TakeWhile(prime => prime * prime <= candidate).
   Where(trialDivisor => candidate % trialDivisor == 0).Count() == 0);

 Console.WriteLine("IEnumerable oddsFrom3:");
 foreach (int p in primes.Take(20))
 {
  Console.WriteLine("{0}", p);
  cache.Add(p);
 }
}

private static void IObservableSieve()
{
 const int bigMax = 1 << 30;

 // Generate the candidates as observables, cache the primes in an IEnum list as before.
 // But it's TERRIBLE that the cache is now of a different TYPE than the thing it's caching.
 // The cache is IEnumerable, and the thing it's caching is an IObservable. 

 IObservable<int> oddsFrom3 = Observable.Range(3, bigMax).Where(i => i % 2 == 1);
 List<int> cache = new List<int>() { 2 };

 IObservable<int> primes = oddsFrom3.
  Where(candidate => cache.
   TakeWhile(prime => prime * prime <= candidate).
   Where(trialDivisor => candidate % trialDivisor == 0).Count() == 0);

 Console.WriteLine("IObservable oddsFrom3 ");

 primes.Take(20).Subscribe(p => { Console.WriteLine("{0}", p); cache.Add(p); });
}

static IEnumerable<int> IntsFrom(int i, int increment)
{
 while (true)
 {
  yield return i;
  i += increment;
 }
}

任何提示?

4

1 回答 1

1

我找到了。LinqPad 中的 F4 会弹出一个添加引用对话框,从那里一切正常。

于 2010-11-02T17:25:23.970 回答