我有一个LPCSTR
我想转换为std::string
orchar*
的。
LPCSTR strName;
_tprintf(_T("%s\n"), strName);
我想把电脑上所有的音频设备都弄出来并显示出来,但是要LPCSTR
直接输出的类型是乱码,用上面的代码输出正确的结果。
有没有办法保存正确的输出?
以下是完整代码:
Add a dependency to the property:
comctl32.lib;winmm.lib;dsound.lib;dxguid.lib;odbc32.lib;odbccp32.lib
ListSoundDev.h
#ifndef _LISTSOUNDDEV_HEAD_
#define _LISTSOUNDDEV_HEAD_
#include<tchar.h>
#include <dshow.h>
#include<iostream>
#include<vector>
#include<mmsystem.h>
#include<mmreg.h>
#include<dsound.h>
#pragma comment(lib, "strmiids.lib")
#pragma comment(lib, "Quartz.lib")
#pragma comment(lib, "winmm.lib")
#pragma comment(lib, "dsound.lib")
#pragma comment(lib, "dxguid.lib")
#pragma comment(lib, "strmiids")
using namespace std;
typedef struct _DevItem
{
LPCSTR strName;
GUID guid;
} DevItem;
#endif
主文件
#include"ListSoundDev_head.h"
std::vector<DevItem> m_CapDevices;
BOOL CALLBACK DSEnumCallback(LPGUID lpGuid, LPCSTR lpcstrDescription, LPCSTR lpcstrModule, LPVOID lpContext)
{
std::vector<DevItem> *pLst = (std::vector<DevItem> *) lpContext;
if (pLst)
{
DevItem item;
memset(&item, 0, sizeof(item));
item.strName = lpcstrDescription;
if (lpGuid)
item.guid = *lpGuid;
else
item.guid = GUID_NULL;
pLst->push_back(item);
return TRUE;
}
return FALSE;
}
int main()
{
std::vector<DevItem>::iterator it;
HRESULT hr = S_OK;
setlocale(LC_ALL, "chs");
hr = DirectSoundCaptureEnumerate((LPDSENUMCALLBACKW)DSEnumCallback, (LPVOID)&m_CapDevices);
for (it = m_CapDevices.begin(); it != m_CapDevices.end(); it++){
_tprintf(_T("%s\n"), it->strName);//output correct
printf("%s\n",it->strName);//output error
std::cout << it->strName << std::endl;//output error
}
}
预期输出:
麦克风 (Realtek High Definition Au
实际输出:
KQ螛</p>
预期输出:
瑞昱数字输入(瑞昱
实际输出:
R
我怎样才能 printf()
或者std::cout
可以直接输出正确的结果?