2

到目前为止，我有以下代码片段：

Sql2o sql2o = new Sql2o("jdbc:sqlite:test.db");

try (Connection connection = sql2o.open()) {
    for (Column column : connection.createQuery("SELECT * FROM sometable").executeAndFetchTable().columns())
        System.out.println(column.toString());
}

我正在使用这些依赖项：

<dependency>
    <groupId>org.sql2o</groupId>
    <artifactId>sql2o</artifactId>
    <version>1.5.4</version>
</dependency>
<dependency>
    <groupId>org.xerial</groupId>
    <artifactId>sqlite-jdbc</artifactId>
    <version>3.15.1</version>
</dependency>

但是，这会在执行时引发 NoInitialContextException。堆栈跟踪：

Exception in thread "main" java.lang.RuntimeException: javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file:  java.naming.factory.initial
        at org.sql2o.JndiDataSource.getJndiDatasource(JndiDataSource.java:27)
        at org.sql2o.Sql2o.<init>(Sql2o.java:36)
        at me.mypackage.sqlitetest.SqliteTest.main(SqliteTest.java:11)
Caused by: javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file:  java.naming.factory.initial
        at javax.naming.spi.NamingManager.getInitialContext(Unknown Source)
        at javax.naming.InitialContext.getDefaultInitCtx(Unknown Source)
        at javax.naming.InitialContext.getURLOrDefaultInitCtx(Unknown Source)
        at javax.naming.InitialContext.lookup(Unknown Source)
        at org.sql2o.JndiDataSource.getJndiDatasource(JndiDataSource.java:24)
        ... 2 more

我该如何解决这个问题？

4

1 回答 1

5

尝试替换此行

Sql2o sql2o = new Sql2o("jdbc:sqlite:test.db");

和

Sql2o sql2o = new Sql2o("jdbc:sqlite:test.db", null, null);

该类Sql2o有一个构造函数，它只接受一个字符串，但是该单个字符串是 JNDI 名称，而不是 JDBC 连接 URL。还有另一个构造函数，它接受三个字符串，用于连接 URL、用户名和密码。SQLite 不使用用户名和密码，因此我们可以null为它们指定值。

于 2016-11-22T22:04:52.143 回答