3

I want to compare in groovy code my Soap Response with xml file ignoring order :

Here is my code :

import org.custommonkey.xmlunit.Stuff
import org.xmlunit.Stuff

//ExpectedString is my xml converted to text, same for ResponseString

Diff diff = DiffBuilder.compare(ExpectedString)
           .withTest(ResponseString)
           .ignoreComments()
           .ignoreWhitespace()
           .checkForSimilar()
           .withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byName))
           .build();

assertFalse("XML similar " + diff.toString(), diff.hasDifferences())

So, as you can see, I used DefaultNodeMatcher, I used XMLUnit2.0 ... with no result (even not ignoring order or having exception error while comparing)

Is there a solution ? to resolve this

As I'm desperate to find a direct one, can I sort my xml and my soap response so i can have a simple diff ? is there a way to sort it line by line alphabetically ? If yes, how ?

Thank you guys !

Update :

Here is my XML structure simplified

<body>
<stuff>
  <miniStuff></miniStuff>
  <miniStuff></miniStuff>
</stuff>
<Services>
  <Service>
    <tag1>ValueA</tag1>
    <tag2>ValueAA</tag2>
  </Service>
  <Service>
    <tag1>ValueB</tag1>
    <tag2>ValueBB</tag2>
  </Service>
</services>
</body>

My problem is I can't guarantee that ValueA is the first one and not the second

4

1 回答 1

6

这是您可能要寻找的：使用ByNameAndTextRecSelector

withNodeMatcher(new DefaultNodeMatcher(new ByNameAndTextRecSelector(),ElementSelectors.byName))

单元测试：

    @Test
    public void testDiffOrder() {
        final String control = """
            <r>
                <ser>
                    <t1>a</t1>
                    <t2>b</t2>
                </ser>
                <ser>
                    <t1>d</t1>
                    <t2>e</t2>
                </ser>
            </r>"""
        final String test = """
            <r>
                <ser>
                    <t1>d</t1>
                    <t2>e</t2>
                </ser>
                <ser>
                    <t1>a</t1>
                    <t2>b</t2>
                </ser>
            </r>"""
        Diff diff = DiffBuilder.compare(Input.fromString(control))
                .withTest(Input.fromString(test))
                .ignoreComments()
                .ignoreWhitespace()
                .checkForSimilar()
                .withNodeMatcher(new DefaultNodeMatcher(new ByNameAndTextRecSelector(),ElementSelectors.byName))
                .build()

        assertFalse("XML differ " + diff.toString(), diff.hasDifferences())
    }

感谢@bodewig。样品从这里

更新：带有 OPs 原始 xml 片段的更 groovified 版本。

import org.xmlunit.builder.DiffBuilder
import org.xmlunit.builder.Input
import org.xmlunit.diff.ByNameAndTextRecSelector
import org.xmlunit.diff.DefaultNodeMatcher
import org.xmlunit.diff.ElementSelectors

def control = """<body>
   <stuff>
      <miniStuff />
      <miniStuff />
   </stuff>
   <Services>
      <Service>
         <tag1>ValueB</tag1>
         <tag2>ValueBB</tag2>
      </Service>
      <Service>
         <tag1>ValueA</tag1>
         <tag2>ValueAA</tag2>
      </Service>
   </Services>
</body>"""
def test = """<body>
   <stuff>
      <miniStuff />
      <miniStuff />
   </stuff>
   <Services>
      <Service>
         <tag1>ValueA</tag1>
         <tag2>ValueAA</tag2>
      </Service>
      <Service>
         <tag1>ValueB</tag1>
         <tag2>ValueBB</tag2>
      </Service>
   </Services>
</body>"""
def myDiff = DiffBuilder.compare(Input.fromString(control))
            .withTest(Input.fromString(test))
            .checkForSimilar()
            .withNodeMatcher(new DefaultNodeMatcher(new ByNameAndTextRecSelector(),ElementSelectors.byName))
            .build()
println myDiff.toString()
println myDiff.hasDifferences()
assert !myDiff.hasDifferences()
于 2016-11-22T15:19:42.133 回答