我想出了这个简单的解决方案——不使用 JSON。仅使用一个输入。希望它会帮助别人。
我必须添加到这种类型:
type Option {
id: ID!
status: String!
products: [Product!]!
}
我们可以添加到突变类型并添加输入,如下所示:
type Mutation {
createOption(data: [createProductInput!]!): Option!
// other mutation definitions
}
input createProductInput {
id: ID!
name: String!
price: Float!
producer: ID!
status: String
}
然后可以使用以下解析器:
const resolvers = {
Mutation: {
createOption(parent, args, ctx, info) {
const status = args.data[0].status;
// Below code removes 'status' from all array items not to pollute DB.
// if you query for 'status' after adding option 'null' will be shown.
// But 'status': null should not be added to DB. See result of log below.
args.data.forEach((item) => {
delete item.status
});
console.log('args.data - ', args.data);
const option = {
id: uuidv4(),
status: status, // or if using babel status,
products: args.data
}
options.push(option)
return option
},
// other mutation resolvers
}
现在您可以使用它来添加一个选项(STATUS 取自数组中的第一项 - 它可以为空):
mutation{
createOption(data:
[{
id: "prodB",
name: "componentB",
price: 20,
producer: "e4",
status: "CANCELLED"
},
{
id: "prodD",
name: "componentD",
price: 15,
producer: "e5"
}
]
) {
id
status
products{
name
price
}
}
}
产生:
{
"data": {
"createOption": {
"id": "d12ef60f-21a8-41f3-825d-5762630acdb4",
"status": "CANCELLED",
"products": [
{
"name": "componentB",
"price": 20,
},
{
"name": "componentD",
"price": 15,
}
]
}
}
}
无需说要获得上述结果,您需要添加:
type Query {
products(query: String): [Product!]!
// others
}
type Product {
id: ID!
name: String!
price: Float!
producer: Company!
status: String
}
我知道这不是最好的方法,但我没有在文档中找到这样做的方法。