0
win=GraphWin("test",410,505)

while win.checkMouse==None:
    rectangle=Rectangle(Point(100,100),Point(300,300))
    rectangle.draw(win)
    rectangle.undraw()
coordinate=win.checkMouse()

坐标保持打印无。如何获取win.checkMouse()按下窗口时的坐标?

4

2 回答 2

1
win=GraphWin("test",410,505)

coordinate = win.checkMouse()
while coordinate == None:
    rectangle=Rectangle(Point(100,100),Point(300,300))
    rectangle.draw(win)
    rectangle.undraw()
    coordinate = win.checkMouse()
print coordinate

尝试这个。

checkMouse() 函数返回最后一次鼠标单击,如果自上次调用后未单击鼠标,则返回 None。因此,在退出 while 循环时,它会将 clicked 值设为 None。

于 2016-11-17T13:07:23.080 回答
0

你先忘()win.checkMouse()

在您的示例中,您必须单击两次,因为第一次单击(和坐标)被循环中win.checkMouse()的第一次捕获。while第二次点击将被coordinate = win.checkMouse()

from graphics import *
import time

win = GraphWin("test", 410, 505)

while not win.checkMouse():
    rectangle = Rectangle(Point(100, 100), Point(300, 300))
    rectangle.draw(win)
    rectangle.undraw()

# time for second click
time.sleep(2)

coordinate = win.checkMouse()
print("coordinate:", coordinate)

win.close()

编辑:没有的例子sleep()

from graphics import *

win = GraphWin("test", 410, 505)

rectangle = Rectangle(Point(100, 100), Point(300, 300))
rectangle.draw(win)

while True:
    coordinate = win.checkMouse()
    if coordinate:
        print("coordinate:", coordinate)
        break

win.close()

编辑:绑定功能到鼠标按钮

from graphics import *

# --- functions ---

def on_click_left_button(event):
    x = event.x
    y = event.y
    rectangle = Rectangle(Point(x, y), Point(x+100, y+100))
    rectangle.draw(win)

def on_click_right_button(event):
    win.close()
    win.quit()

# --- main ---

win = GraphWin("test", 410, 505)

win.bind('<Button-1>', on_click_left_button)
win.bind('<Button-3>', on_click_right_button)

win.mainloop()
于 2016-11-17T12:05:24.517 回答