android - 如何在Android应用程序中访问下载的音频文件夹

Question

我正在开发一个简单的音频流 android 应用程序。从 URL 播放音频时，该应用程序还可以选择下载文件。音频文件正在下载到Internal Storage/voices文件夹中。如何在我的应用程序中显示此文件夹的所有下载音频？我想访问语音文件夹中的所有音频并显示在我的应用程序中，这样用户就不需要手动搜索文件。请指导。谢谢！

Answer 1

String path = Environment.getExternalStorageDirectory().toString()+"/voices";
Log.d("Files", "Path: " + path);
File directory = new File(path);
File[] files = directory.listFiles();
Log.d("Files", "Size: "+ files.length);
for (int i = 0; i < files.length; i++)
{
    Log.d("Files", "FileName:" + files[i].getName());
}

这样，您将把voices目录中存储的所有文件放入files数组中。

Answer 2

我使用以下代码做到了：

 private ListView mainListView ;
private ArrayAdapter<String> listAdapter ;
private MediaPlayer mp = new MediaPlayer();
private List<String> ListOfFiles = new ArrayList<String>();
String path = Environment.getExternalStorageDirectory().toString()+"/voices";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);


    // Find the ListView resource.
    mainListView = (ListView) findViewById( R.id.mainListView );


    Log.d("Files", "Path: " + path);
    File directory = new File(path);
    File[] files = directory.listFiles();
    Log.d("Files", "Size: "+ files.length);
    for (int i = 0; i < files.length; i++)
    {
        Log.d("Files", "FileName:" + files[i].getName());
    }

    for (int i = 0; i < files.length; i++) {
        ListOfFiles.add(files[i].getName());
    }


    listAdapter = new ArrayAdapter<String>(this, R.layout.row_layout, ListOfFiles);
    mainListView.setAdapter( listAdapter );


    mainListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        @Override
        public void onItemClick(AdapterView<?> parent, View view,
                                int position, long id) {
            playSong(path +"/"+ ListOfFiles.get(position));

            Log.d("Path",path + ListOfFiles.get(position));
        }
    });
}

private void playSong(String songPath) {
    try {
        mp.reset();
        mp.setDataSource(songPath);
        mp.prepare();
        mp.start();
    } catch (IOException e) {
        Log.v(getString(R.string.app_name), e.getMessage());
    }
}