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我正在尝试编译 Tox(特别是 toxcore)。当我尝试编译它时,遇到以下错误:

>make
make  all-recursive
make[1]: Entering directory '/root/Tox/toxcore'
Making all in build
make[2]: Entering directory '/root/Tox/toxcore/build'
  CCLD     libtoxav.la
/usr/bin/ld: /usr/local/lib/libvpx.a(vpx_codec.c.o): relocation R_X86_64_32 against `.rodata.str1.1' can not be used when making a shared object; recompile with -fPIC
/usr/local/lib/libvpx.a: error adding symbols: Bad value
collect2: error: ld returned 1 exit status
Makefile:1385: recipe for target 'libtoxav.la' failed
make[2]: *** [libtoxav.la] Error 1
make[2]: Leaving directory '/root/Tox/toxcore/build'
Makefile:506: recipe for target 'all-recursive' failed
make[1]: *** [all-recursive] Error 1
make[1]: Leaving directory '/root/Tox/toxcore'
Makefile:410: recipe for target 'all' failed
make: *** [all] Error 2

在错误消息之后,我尝试fPIC通过导出 C++ 标志 ( )、向( )export CXXFLAGS="$CXXFLAGS -fPIC"添加参数和编辑(更改为)来使用,但这些尝试没有奏效,我仍然遇到相同的错误。可能出了什么问题?configure./configure --enable-sharedMakefileCC = gccCC = gcc -fPIC

这是我现在的方法(在 Ubuntu 上):

sudo apt-get install pkg-config
sudo apt-get install build-essential
sudo apt-get install libtool
sudo apt-get install autotools-dev
sudo apt-get install automake
sudo apt-get install checkinstall
sudo apt-get install check
sudo apt-get install git
sudo apt-get install yasm

cd ~
mkdir Tox
cd Tox

git clone https://github.com/jedisct1/libsodium.git
cd libsodium
git checkout tags/1.0.3
./autogen.sh
./configure && make check
sudo checkinstall --install --pkgname libsodium --pkgversion 1.0.0 --nodoc
sudo ldconfig
cd ..

git clone https://chromium.googlesource.com/webm/libvpx
cd libvpx
git checkout tags/v1.3.0
./configure
make
make install
cd ..

git clone https://github.com/irungentoo/toxcore.git
cd toxcore
autoreconf -i
./configure
make
sudo make install
cd ..
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2 回答 2

0

配置 with--enable-pic将添加必要的 -fPIC 选项,并且对我有用。

于 2018-01-29T18:04:10.297 回答
0

配置脚本中一定有错误,它不应该出现 libvpx.a.

但不用担心,因为 Ubuntu 为libvpx-dev和提供了软件包libsodium-dev,并且使用它们似乎工作得很好,所以你可能应该这样做,除非有充分的理由不这样做。

此外,除非您需要classic toxcore,否则它似乎c-toxcore是继任者,因此您可能应该改用它。

于 2016-11-28T07:16:42.117 回答