3

在 Odoo 8 中，我能够使用 XML 定义服务器操作，例如：

<?xml version="1.0" encoding="utf-8" ?>
<odoo>
  <data>
    <record id="action" model="ir.actions.server">
      <field name="name">My Action</field>
      <field name="model_id" ref="model_module_model"/>
      <field name="code">self.action(cr, uid, context=context)</field>
    </record>
  </data>
</odoo>

这将执行我的 module.model.action() 方法。

在 Odoo 10 中，此代码引发异常：

ERROR:odoo.http:Exception during JSON request handling.
Traceback (most recent call last):
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 638, in _handle_exception
    return super(JsonRequest, self)._handle_exception(exception)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 675, in dispatch
    result = self._call_function(**self.params)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 331, in _call_function
    return checked_call(self.db, *args, **kwargs)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/service/model.py", line 119, in wrapper
    return f(dbname, *args, **kwargs)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 324, in checked_call
    result = self.endpoint(*a, **kw)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 933, in __call__
    return self.method(*args, **kw)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/http.py", line 504, in response_wrap
    response = f(*args, **kw)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/addons/web/controllers/main.py", line 1129, in run
    result = request.env['ir.actions.server'].browse([action_id]).run()
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/addons/base/ir/ir_actions.py", line 964, in run
    res = func(action, eval_context=eval_context)
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/addons/base/ir/ir_actions.py", line 793, in run_action_code_multi
    safe_eval(action.code.strip(), eval_context, mode="exec", nocopy=True)  # nocopy allows to return 'action'
File "/usr/share/odoo/lib/python2.7/site-packages/odoo/tools/safe_eval.py", line 301, in safe_eval
    return unsafe_eval(c, globals_dict, locals_dict)
File "", line 1, in <module>
ValueError: <type 'exceptions.NameError'>: "name 'self' is not defined" while evaluating
u'self.action(cr, uid, context=context)'

我在https://www.odoo.com/documentation/10.0/reference/actions.html#code的有关服务器操作的 Odoo 文档中没有看到任何有趣的内容

并且文档明确声明 self 是服务器操作的评估上下文的一部分，请参阅https://www.odoo.com/documentation/10.0/reference/actions.html#reference-actions-server-context

如何在 Odoo 10 中创建服务器操作？

4

3 回答 3

8

在 Odoo 10 中声明服务器操作时不需要self对象。我们可以使用env['model.name']直接访问模型/对象

尝试使用以下代码：

<?xml version="1.0" encoding="utf-8" ?>
<odoo>
  <data>
    <record id="action" model="ir.actions.server">
      <field name="name">My Action</field>
      <field name="model_id" ref="model_module_model"/>
      <field name="code">
        if context.get('active_model') == 'your.module.model' and context.get('active_ids'):
                action = env['module.model'].browse(context['active_ids']).action()
    </record>
  </data>
</odoo>

编辑：

我们可以在没有active_ids时使用这些env['module.model'].action()来执行方法

于 2016-11-13T07:39:08.973 回答
1

自 Odoo 10 以来，旧 API 已被完全删除。所以我猜你使用 cr、uid 和上下文的旧式调用是问题所在。尝试只调用模型，或者如果有要调用方法的记录，请使用它。

# model call
model.action()
# record call
object.action()

一点提示：尝试在客户端的设置下创建服务器操作。输入“代码”是默认设置，您将获得有关此功能的一些文档 :-)

于 2016-11-13T08:06:01.127 回答
1 
# model call
 <field name="code">
     model.action_name()
 </field>

# record call
 <field name="code">
    record.action_name()
 </field>
于 2016-12-21T03:18:17.670 回答