0

这是我的代码: final Intent intent = new Intent(this, SelectWidgetActivity.class); startActivityForResult(intent, REQUEST_CREATE_APPWIDGET);

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {

    if (resultCode == RESULT_OK ) {
        String selectedName = data.getStringExtra(SelectWidgetActivity.SELECTED_WIDGET);
        if(!mAppWidgetManager.bindAppWidgetIdIfAllowed(appWidgetId, info.provider)) {
                    Intent bindIntent = new Intent(AppWidgetManager.ACTION_APPWIDGET_BIND);
                    bindIntent.putExtra(AppWidgetManager.EXTRA_APPWIDGET_ID, appWidgetId);
                    bindIntent.putExtra(AppWidgetManager.EXTRA_APPWIDGET_PROVIDER, info.provider);
                    bindIntent.putExtra(SelectWidgetActivity.SELECTED_WIDGET, selectedName);
                    startActivityForResult(bindIntent, REQUEST_BIND_APPWIDGET);
        }
    }
}

我将 String 放在 startActivityForResult 的第一次调用中,而在第二次调用中,我试图获取相同的字符串,但为空。例如在第一次调用 selectedName="Calendar" 时,第二次调用 onActivityResult() selectedName=null

有任何想法吗?

4

1 回答 1

3

您甚至必须检查您在拨打此电话时发送的 onActivityResult 中的 requestCode

startActivityForResult(intent, REQUEST_CREATE_APPWIDGET);

尝试这个

  if (requestCode == REQUEST_CREATE_APPWIDGET && resultCode == Activity.RESULT_OK) {
        //do your work here;
    }
于 2016-11-09T13:25:32.550 回答