我正在使用下面的查询来提取帐户列表以及与它们一起使用的可选代码。每个帐户有 95 个代码，而不仅仅是我在下面的结果中显示的 2 个。
SELECT DISTINCT Ref1.ACCOUNT_ID as Acct_Numb,
Current_Date as DATA_DATE,
Cat.OPTIONAL_CTGRY_CD As Code,
Cat.OPTIONAL_CTGRY_CD || ' - ' || Cat.OPTIONAL_CTGRY_NM AS Code_Combo,
Class.OPTIONAL_CLASS_CD as Code_Answer,
Class.OPTIONAL_CLASS_NM as Code_Answer_Desc
FROM xxxxx.zzzzzz_OPT_REF Ref1
LEFT JOIN xxxxx.zzzzzz_OPT_CATEGORY Cat
ON xxxxx.zzzzzz_OPT_REF.OPTIONAL_CTGRY_CD = xxxxx.zzzzzz_OPT_CATEGORY.OPTIONAL_CTGRY_CD
LEFT JOIN xxxxx.zzzzzz_OPT_CLASS Class
ON xxxxx.zzzzzz_OPT_REF.OPTIONAL_CLASS_CD = xxxxx.zzzzzz_OPT_CLASS.OPTIONAL_CLASS_CD
AND xxxxx.zzzzzz_OPT_CATEGORY.OPTIONAL_CTGRY_CD = xxxxx.zzzzzz_OPT_CLASS.OPTIONAL_CTGRY_CD
LEFT JOIN xxxxx.HRTVACT_PCS Acct
ON xxxxx.ACCOUNT_ID = Acct.ACCOUNTID
WHERE xxxxx.ACCOUNTSTATUS = 'OPEN' AND xxxxx.ACCOUNTID = '123456' OR xxxxx.ACCOUNTID = '654321'
ORDER BY ACCT_NUMB ASC, CODE ASC;
这是结果
DATA_DATE ACCT_NUMB CODE CODE_COMBO CODE_ANSWER CODE_ANSWER_DESC
11/8/2016 123456 1 1 - Reporting 0 NOT APPLICABLE
11/8/2016 123456 2 2 - System 4 SYSTEM 2
11/8/2016 654321 1 1 - Reporting 3 APPLIED
11/8/2016 654321 2 2 - System 3 N/A
我需要将结果创建为如下表所示的数据透视表。
(CODE) (CODE_COMBO) (CODE) (CODE_COMBO)
DATA_DATE ACCT_NUMB 1 1 - Reporting 2 2 - System
11/8/2016 123456 0 NOT APPLICABLE 4 SYSTEM 2 (CODE_ANSWER)/(CODE_ANSWER_DESC)
11/8/2016 654321 3 APPLIED 3 N/A (CODE_ANSWER)/(CODE_ANSWER_DESC)
我以前没有试过这个，我很难过