我能够让连接消除适用于简单的情况，例如一对一关系，但不适用于稍微复杂的场景。最终我想尝试锚建模，但首先我需要找到解决这个问题的方法。我正在使用 Oracle 12c Enterprise Edition Release 12.1.0.2.0。
我的测试用例的 DDL：
drop view product_5nf;
drop table product_color cascade constraints;
drop table product_price cascade constraints;
drop table product cascade constraints;
create table product(
product_id number not null
,constraint product_pk primary key(product_id)
);
create table product_color(
product_id number not null references product
,color varchar2(10) not null
,constraint product_color_pk primary key(product_id)
);
create table product_price(
product_id number not null references product
,from_date date not null
,price number not null
,constraint product_price_pk primary key(product_id, from_date)
);
一些示例数据：
insert into product values(1);
insert into product values(2);
insert into product values(3);
insert into product values(4);
insert into product_color values(1, 'Red');
insert into product_color values(2, 'Green');
insert into product_price values(1, date '2016-01-01', 10);
insert into product_price values(1, date '2016-02-01', 8);
insert into product_price values(1, date '2016-05-01', 5);
insert into product_price values(2, date '2016-02-01', 5);
insert into product_price values(4, date '2016-01-01', 10);
commit;
5NF 观点
第一个视图无法编译 - 它失败并出现 ORA-01799: a column may not be outer-joined to a subquery。不幸的是，当我查看锚建模的在线示例时，这就是大多数历史视图的定义方式......
create view product_5nf as
select p.product_id
,pc.color
,pp.price
from product p
left join product_color pc on(
pc.product_id = p.product_id
)
left join product_price pp on(
pp.product_id = p.product_id
and pp.from_date = (select max(pp2.from_date)
from product_price pp2
where pp2.product_id = pp.product_id)
);
下面是我修复它的尝试。当通过简单的选择来使用这个视图时product_id，Oracle 设法消除了 product_color 而不是product_price。
create view product_5nf as
select product_id
,pc.color
,pp.price
from product p
left join product_color pc using(product_id)
left join (select pp1.product_id, pp1.price
from product_price pp1
where pp1.from_date = (select max(pp2.from_date)
from product_price pp2
where pp2.product_id = pp1.product_id)
)pp using(product_id);
select product_id
from product_5nf;
----------------------------------------------------------
| Id | Operation | Name | Rows |
----------------------------------------------------------
| 0 | SELECT STATEMENT | | 4 |
|* 1 | HASH JOIN OUTER | | 4 |
| 2 | INDEX FAST FULL SCAN| PRODUCT_PK | 4 |
| 3 | VIEW | | 3 |
| 4 | NESTED LOOPS | | 3 |
| 5 | VIEW | VW_SQ_1 | 5 |
| 6 | HASH GROUP BY | | 5 |
| 7 | INDEX FULL SCAN | PRODUCT_PRICE_PK | 5 |
|* 8 | INDEX UNIQUE SCAN | PRODUCT_PRICE_PK | 1 |
----------------------------------------------------------
我发现的唯一解决方案是使用标量子查询，如下所示：
create or replace view product_5nf as
select p.product_id
,pc.color
,(select pp.price
from product_price pp
where pp.product_id = p.product_id
and pp.from_date = (select max(from_date)
from product_price pp2
where pp2.product_id = pp.product_id)) as price
from product p
left join product_color pc on(
pc.product_id = p.product_id
)
select product_id
from product_5nf;
---------------------------------------------------
| Id | Operation | Name | Rows |
---------------------------------------------------
| 0 | SELECT STATEMENT | | 4 |
| 1 | INDEX FAST FULL SCAN| PRODUCT_PK | 4 |
---------------------------------------------------
现在 Oracle 成功地消除了 product_price 表。但是，标量子查询的实现方式与连接不同，它们的执行方式根本不允许我在现实世界的场景中获得任何可接受的性能。
TL;DR
我如何重写视图product_5nf以使 Oracle 成功地消除这两个依赖表？