python - 我如何编写一个算法来读取三个数字并在python中按升序打印出来

Question

我如何编写一个算法来读取三个数字并在 python 中按升序打印出来。请帮助这是我迄今为止尝试过的，希望你们能帮助我，谢谢，这是使用python，我是编程新手。我不知道如何做它在升序中所说的部分。

one = float(input("Please input a number : "))
two = float(input("Please input a second number : "))
three = float(input("Please input a third number : "))

if one > two and three:
    print("")*

Answer 1

根据您的代码，以下代码将按升序顺序打印数字一和二。我建议你尝试完成三个元素的代码。

one = float(input("Please input a number : "))
two = float(input("Please input a second number : "))
three = float(input("Please input a third number : "))

if one < two:
    print(one, two)
else:
    print(two, one)

你的举动...

Answer 2

你可以使用 sorted()，但首先你将数字保存在一个列表中，试试这个：

nums = []
one = nums.append(float(input("Please input a number : ")))
two = nums.append(float(input("Please input a second number : ")))
three = nums.append(float(input("Please input a third number : ")))
for num in sorted(nums):
    print (num)

sorted() - Python 文档

如果您需要使用 if 和 else 语句，您应该考虑输入数字的所有组合并评估它，试试这个：

one = float(input("Please input a number : "))
two = float(input("Please input a second number : "))
three = float(input("Please input a third number : "))

if one < two and three < two:
    if one > three:
        print(three, one, two)
    else:
        print(one, three, two)
elif one < three and two < three:
    if one > two:
        print(two, one, three)
    else:
        print(one, two, three)        
elif two < one and three < one:
    if three > two:
        print(two, three, one)
    else:
        print(three, two, one)
else:
    print(one, two, three)