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我有一个实体：

@Entity public class KnowledgeBase {

    private Long id;
    private String link;
    private String content;

    @Id
    @SequenceGenerator(name = "knowledgebase_id_generator", sequenceName = "knowledgebase_id_sequence", allocationSize = 1)
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "knowledgebase_id_generator")
    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public String getLink() {
        return link;
    }

    public void setLink(String link) {
        this.link = link;
    }

    public String getContent() {
        return content;
    }

    public void setContent(String content) {
        this.content = content;
    }
}

我有一个弹簧数据存储库

@Repository public interface KnowledgeBaseRepository
        extends AbstractRepository<KnowledgeBase, Long> {

    @Query(value = "SELECT c.id as id,c.link as link, c.content as content"
            + " from knowledgebase c where content=?1", nativeQuery = true)
    List<KnowledgeBase> findRelevantRecords(String searchString);
}

请注意

where content=?1

只是一个示例，where 子句对于测试是不同的。

问题是如果我运行这个存储库方法，一切都很好，但是内容列包含大量文本，我希望它被延迟加载。如果我这样做，我会收到错误，即 Long:'' 的值是错误的。所以我的实体是：

@Lob @Basic(fetch = LAZY) String content;

如果我删除它，一切都会好起来的。如何防止每次都加载内容列并正确进行spring数据存储库搜索？

4

1 回答 1

1

试试这个：在你的实体中创建一个只接受必填字段的构造函数

public class KnowledgeBase{

//default constructor
public KnowledgeBase(){}

public KnowledgeBase(Long id,String link){
this.id=id;
this.link=link;
}

}

并在存储库的查询中使用此构造函数签名

 @Query(value = "SELECT new #{#entityName} (c.id as id,c.link as link) from #{#entityName} c "
            + " from knowledgebase c where content=?1", nativeQuery = true)
    List<KnowledgeBase> findRelevantRecordsWithoutContent(String searchString);
于 2016-11-06T23:25:41.443 回答