3

我在我的项目中安装了 Alamofire,现在这就是我所做的。

我安装了邮递员,然后将我的网址和正文放入了一个 xml 对象,然后得到了结果。

这是我对邮递员所做的事情的照片

在此处输入图像描述

我现在如何使用 Alamofire 或 SWXMLHash 发送它,因为我用邮递员发送它

提前致谢!

编辑

我从另一个问题尝试了这个:

 Alamofire.request(.POST, "https://something.com" , parameters: Dictionary(), encoding: .Custom({
            (convertible, params) in
            let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest

            let data = (self.testString as NSString).dataUsingEncoding(NSUTF8StringEncoding)
            mutableRequest.HTTPBody = data
            return (mutableRequest, nil)
        }))


    .responseJSON { response in


    print(response.response) 

    print(response.result)   


    }
}

但它没有发送任何东西

这是日志:

可选({ URL: https://something.com } { 状态代码:200,标头 { Connection = “keep-alive”;“Content-Length” = 349;“Content-Type” = “application/xml”;日期=“格林威治标准时间 2016 年 11 月 2 日星期三 21:13:32”;服务器 = nginx;“Strict-Transport-Security”=“max-age=31536000;includeSubDomains”;} })

失败

编辑

永远不要忘记传递参数,如果你没有简单的添加这个,参数:Dictionary()

4

3 回答 3

8

使用 Swift 3 和 Alamofire 4

    let stringParams : String = "<msg id=\"123123\" reqTime=\"123123\">" +
        "<params class=\"API\">" + 
        "<param name=\"param1\">123213</param>" + 
        "<param name=\"param2\">1232131</param>" +
        "</params>" +
    "</msg>"

    let url = URL(string:"<#URL#>")
    var xmlRequest = URLRequest(url: url!)
    xmlRequest.httpBody = stringParams.data(using: String.Encoding.utf8, allowLossyConversion: true)
    xmlRequest.httpMethod = "POST"
    xmlRequest.addValue("application/xml", forHTTPHeaderField: "Content-Type")


    Alamofire.request(xmlRequest)
            .responseData { (response) in
                let stringResponse: String = String(data: response.data!, encoding: String.Encoding.utf8) as String!
                debugPrint(stringResponse)
    }
于 2017-06-07T06:37:28.737 回答
6

使用 Swift 3 和 Alamofire 4,您将创建一个自定义ParameterEncoding. 与任何其他 XML 编码主体一样,SOAP 消息可以使用此参数编码,如下例所示。可以类似地创建其他 XML 正文编码(检查它所说的行urlRequest.httpBody = ...):

struct SOAPEncoding: ParameterEncoding {
    let service: String
    let action: String

    func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest {
        var urlRequest = try urlRequest.asURLRequest()

        guard let parameters = parameters else { return urlRequest }

        if urlRequest.value(forHTTPHeaderField: "Content-Type") == nil {
            urlRequest.setValue("text/xml", forHTTPHeaderField: "Content-Type")
        }

        if urlRequest.value(forHTTPHeaderField: "SOAPACTION") == nil {
            urlRequest.setValue("\(service)#\(action)", forHTTPHeaderField: "SOAPACTION")
        }

        let soapArguments = parameters.map({key, value in "<\(key)>\(value)</\(key)>"}).joined(separator: "")

        let soapMessage =
            "<s:Envelope xmlns:s='http://schemas.xmlsoap.org/soap/envelope/' s:encodingStyle='http://schemas.xmlsoap.org/soap/encoding/'>" +
            "<s:Body>" +
            "<u:\(action) xmlns:u='\(service)'>" +
            soapArguments +
            "</u:\(action)>" +
            "</s:Body>" +
            "</s:Envelope>"

        urlRequest.httpBody = soapMessage.data(using: String.Encoding.utf8)

        return urlRequest
    }
}

然后像这样使用它:

Alamofire.request(url, method: .post, parameters: ["parameter" : "value"], encoding: SOAPEncoding(service: "service", action: "action"))
于 2016-12-31T21:56:56.040 回答
3

假设您在请求中缺少有效的 HTTP 标头,更新后的请求可能如下所示:

Alamofire.request(.POST, "https://something.com", parameters: Dictionary() , encoding: .Custom({
            (convertible, params) in
            let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest

            let data = (self.testString as NSString).dataUsingEncoding(NSUTF8StringEncoding)
            mutableRequest.HTTPBody = data
            mutableRequest.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type")
            return (mutableRequest, nil)
        }))
    .responseJSON { response in
    print(response.response) 
    print(response.result)   
    }
}

所以,基本上你应该添加一行

mutableRequest.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type")

更新
尝试相同,但使用responseDataorresponseString代替,responseJSON因为您的响应可能不是JSON

于 2016-11-03T11:43:05.677 回答