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我正在使用 V4L2 API 从 UVC 设备中抓取帧。我想通过计算帧的时间戳和当前时钟时间之间的偏移量来测量曝光时间。这是我正在使用的代码：

/* Control code snipped */
struct v4l2_buffer buf = {0}
buf.type = V4L2_BUF_TYPE_VIDEO_CAPTURE;
buf.memory = V4L2_MEMORY_MMAP;
ioctl(fd, VIDIOC_DQBUF, &buf);

switch( buf.flags & V4L2_BUF_FLAG_TIMESTAMP_MASK )
{
    case V4L2_BUF_FLAG_TIMESTAMP_MONOTONIC:
    {
        struct timespec uptime = {0};
        clock_gettime(CLOCK_MONOTONIC,&uptime);

        float const secs =
            (buf.timestamp.tv_sec - uptime.tv_sec) +
            (buf.timestamp.tv_usec - uptime.tv_nsec/1000.0f)/1000.0f;

        if( V4L2_BUF_FLAG_TSTAMP_SRC_SOE == (buf.flags & V4L2_BUF_FLAG_TSTAMP_SRC_MASK) )
            printf("%s: frame exposure started %.03f seconds ago\n",__FUNCTION__,-secs);
        else if( V4L2_BUF_FLAG_TSTAMP_SRC_EOF == (buf.flags & V4L2_BUF_FLAG_TSTAMP_SRC_MASK) )
            printf("%s: frame finished capturing %.03f seconds ago\n",__FUNCTION__,-secs);
        else printf("%s: unsupported timestamp in frame\n",__FUNCTION__);

        break;
    }

    case V4L2_BUF_FLAG_TIMESTAMP_UNKNOWN:
    case V4L2_BUF_FLAG_TIMESTAMP_COPY:
    default:
        printf("%s: no usable timestamp found in frame\n",__FUNCTION__);
}

设置为 1 秒的曝光时间返回的示例VIDIOC_S_CTRL：

read_frame: frame exposure started 28.892 seconds ago
read_frame: frame exposure started 28.944 seconds ago
read_frame: frame exposure started 28.895 seconds ago
read_frame: frame exposure started 29.037 seconds ago

我在SRC_SOE时间戳和单调时钟之间得到了奇怪的 30 秒偏移，其中有 1 秒的曝光焊接。V4L2/UVC 时间戳应该是从ktime_get_ts(). 知道我做错了什么吗？

这在 Linux 4.4 Gentoo 系统上运行。网络摄像头是 DMK21AU04.AS，被认为是标准的 UVC 设备。

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1 回答 1

2

事情是......

1 s = 1000ms，
1 ms = 1000us，
1 us = 1000ns。

所以……

应该是……

float const secs =
        (buf.timestamp.tv_sec - uptime.tv_sec) +
        (buf.timestamp.tv_usec - uptime.tv_nsec/1000.0f)/1000000.0f;
于 2017-02-10T12:46:51.187 回答