当我尝试将函数返回值设置为标签输出时，我不断收到此错误。
import UIKit
class finalData: UIViewController {
var userNum: Int!
var computerNum: Int!
@IBOutlet var output: UILabel!
override func viewDidLoad() {
super.viewDidLoad()
self.output.text = chooseWinner(userNum: userNum, computerNum: computerNum)
// Do any additional setup after loading the view.
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
func chooseWinner(userNum : Int, computerNum : Int) -> String {
if userNum == computerNum {
return "There is a tie"
}else if userNum == 1 && computerNum == 2{
return "You lost!"
}else if userNum == 1 && computerNum == 3{
return "You won!"
}else if userNum == 2 && computerNum == 1{
return "You won!"
}
else if userNum == 2 && computerNum == 3{
return "You lost!"
}else if userNum == 3 && computerNum == 1{
return "You lost!"
}
else if userNum == 3 && computerNum == 2{
return "You won!"
}else{
return "value"
}
}
func findPlayerImage (firstImage: Int) -> UIImage{
if userNum == 1{
return #imageLiteral(resourceName: "black")
}else if userNum == 2{
return #imageLiteral(resourceName: "black")
}else{
return #imageLiteral(resourceName: "black")
}
}
func findCompImage (secondImage: Int) -> UIImage{
if computerNum == 1{
return #imageLiteral(resourceName: "black")
}else if computerNum == 2{
return #imageLiteral(resourceName: "black")
}else{
return #imageLiteral(resourceName: "black")
}
}
/*
// MARK: - Navigation
// In a storyboard-based application, you will often want to do a little preparation before navigation
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
// Get the new view controller using segue.destinationViewController.
// Pass the selected object to the new view controller.
}
*/
}
我正在尝试将数字传递给此视图控制器，然后调用该函数以返回一个字符串（我正在制作 Rock、Paper、Scissors）。但是，当我设置输出 = 函数时，它给了我一个展开错误。