3

我正在Tomcat 7运行Windows 7。所有客户端也在运行Windows 7。

我正在尝试在test.jsp页面上打印客户端用户名，因此我使用Waffle. 这里是WEB-INF/web.xml 

 <filter>
  <filter-name>SecurityFilter</filter-name>
  <filter-class>waffle.servlet.NegotiateSecurityFilter</filter-class>
  <init-param>
    <param-name>impersonate</param-name>
    <param-value>true</param-value>
  </init-param>
</filter>

这是我的test.jsp 

<% 
    String userId = Secur32Util.getUserNameEx(Secur32.EXTENDED_NAME_FORMAT.NameSamCompatible); 
    out.println(userId); 
%>

但是它总是打印server计算机用户名。我在很多client机器上都试过了，它总是打印server但不是client 用户标识

为什么？如何纠正这个？

4

2 回答 2

3

首先，将 waffle-api.jar 放在您的项目类路径中。然后将此 xml 代码放在您的 web.xml 上。

<filter>
    <filter-name>SecurityFilter</filter-name>
    <filter-class>waffle.servlet.NegotiateSecurityFilter</filter-class>
    <init-param>
        <param-name>principalFormat</param-name>
        <param-value>fqn</param-value>
    </init-param>
    <init-param>
        <param-name>roleFormat</param-name>
        <param-value>both</param-value>
    </init-param>
    <init-param>
        <param-name>allowGuestLogin</param-name>
        <param-value>true</param-value>
    </init-param>
    <init-param>
        <param-name>securityFilterProviders</param-name>
        <param-value>
        waffle.servlet.spi.NegotiateSecurityFilterProvider
        waffle.servlet.spi.BasicSecurityFilterProvider
    </param-value>
    </init-param>
    <init-param>
        <param-name>waffle.servlet.spi.NegotiateSecurityFilterProvider/protocols</param-name>
        <param-value>
        Negotiate
        NTLM
    </param-value>
    </init-param>
    <init-param>
        <param-name>waffle.servlet.spi.BasicSecurityFilterProvider/realm</param-name>
        <param-value>WaffleFilterDemo</param-value>
    </init-param>
</filter>
<filter-mapping>
    <filter-name>SecurityFilter</filter-name>
    <url-pattern>/*</url-pattern>
</filter-mapping>

并使用以下代码获取您的客户用户名；

HttpServletRequest request = (HttpServletRequest)Executions.getCurrent().getNativeRequest();
String user = request.getRemoteUser();

有关更多详细信息，您可以访问：

https://github.com/dblock/waffle

归功于klepon

资源链接：

  1. http://forum.zkoss.org/question/96532/get-clients-username/
  2. https://stackoverflow.com/a/5891022/2293534
于 2016-10-31T02:31:30.403 回答
1

神奇之处在于：$pageContext.request.remoteUser

于 2016-10-30T19:34:59.687 回答