0

我曾经listagg将书籍与补充书籍名称一起连接和列出。

SELECT DISTINCT SUBSTR(LISTAGG(',-'||B1.BOOK_NO||','||B1.BOOK_NAME||','||A.AUTHOR_NAME||',-'||B2.BOOK_NO||','||B2.BOOK_NAME)   WITHIN GROUP (ORDER BY B2.BOOK_NO),2) 
FROM BOOK_LIST B1
INNER JOIN AUTHORS A ON A.AUTHOR_NO=B1.AUTHOR_NO
INNER JOIN SUPPLEMENTARY B2 ON B2.BOOK_NO = B1.BOOK_SUP_NO
WHERE B1.SEQ = 123;

但由于补充书的数量更多，我反复得到主书名。

有没有办法删除重复的主书名和号码。

我的输出是这样的

-99,Anders Carlson ,-109,John Stuart,-99,Anders Carlson ,-47,James Anderson

这里重复值 99 我只想要一个 99。

期望的输出：

-99,Anders Carlson ,-109,John Stuart,-47,James Anderson

数据库数据：

书单：

NO | MAIN_BOOK_NO | MAIN_BOOK_NAME | BOOK_SUP_NO | AUTHOR_NO
1  |    12        |    xyz         |   5         |   2
2  |    22        |    abc         |   7         |   4

作者：

NO | AUTHOR_NO | AUTHOR_NAME
 1 |  2        | Alex
 2 |  3        | Leonard
 3 |  4        | Benjamin

补充：

NO | BOOK_NO | BOOK_NAME 
1  |   5     |   ABC
2  |   5     |   XYZ
3  |   7     |   LMN
4  |   7     |   DEF
5  |   7     |   NEW

输出应该像

         NAME
12,xyz,Alex,-5,ABC,-5,XYZ
22,abc,Benjamin,-7,LMN,-7,DEF,-7,NEW

同样对于表中的整个数据

4

2 回答 2

1

如果我对您的理解正确，您需要将补充书籍列表附加到主书中，因此您实际上需要以下内容：

SELECT B1.MAIN_BOOK_NO||','||B1.MAIN_BOOK_NAME||',-'||
         LISTAGG(B2.BOOK_NO||','||B2.BOOK_NAME, ',-') WITHIN GROUP (ORDER BY B2.BOOK_NO) 
FROM   BOOK_LIST B1
       INNER JOIN AUTHORS A ON A.AUTHOR_NO=B1.AUTHOR_NO
       INNER JOIN SUPPLEMENTARY B2 ON B2.BOOK_NO = B1.BOOK_SUP_NO
WHERE  B1.SEQ = 123
GROUP BY B1.MAIN_BOOK_NO, B1.MAIN_BOOK_NAME;
于 2016-10-24T11:00:30.837 回答
0

看看这是否有效

select T1.MAIN_BOOK_NO, T11.MAIN_BOOK_NAME, LISTAGG(',-'||',-'||T1.BOOK_NO||','||T1.BOOK_NAME) WITHIN GROUP (order by T1.BOOK_NO)
from
(
SELECT B1.MAIN_BOOK_NO, B1.MAIN_BOOK_NAME, B2.BOOK_NO, B2.BOOK_NAME
FROM BOOK_LIST B1
INNER JOIN AUTHORS A ON A.AUTHOR_NO=B1.AUTHOR_NO
INNER JOIN SUPPLEMENTARY B2 ON B2.BOOK_NO = B1.BOOK_SUP_NO
WHERE B1.SEQ = 123
group by B1.MAIN_BOOK_NO, B1.MAIN_BOOK_NAME, B2.BOOK_NO, B2.BOOK_NAME
order by B2.BOOK_NO
) T1 
group by T1.MAIN_BOOK_NO, T1.MAIN_BOOK_NAME;
于 2016-10-24T11:54:08.207 回答