我想加密一个字符串,但是标准的 Java 库对我来说太复杂了。
所以我转向Jasypt labriry。使用和理解非常简单。但是,当我将库导入 Eclipse 3.6 并尝试使用密码“123”加密像“Hello”这样的字符串时,它总是会出现错误。我不确定我做错了什么,但我认为当我在 Eclipse 中使用其他库时也会发生这种情况。
来源:
import org.jasypt.util.text.BasicTextEncryptor;
public class Main {
static BasicTextEncryptor textEncryptor = new BasicTextEncryptor();
public static void main(String[] args) {
System.out.println("Hello World");
textEncryptor.setPassword("123");
System.out.println(textEncryptor.encrypt("Hello World"));
}
}
错误信息:
java.lang.NoClassDefFoundError: org/apache/commons/lang/exception/NestableRuntimeException
at java.lang.ClassLoader.defineClass1(Native Method)
at java.lang.ClassLoader.defineClassCond(Unknown Source)
at java.lang.ClassLoader.defineClass(Unknown Source)
at java.security.SecureClassLoader.defineClass(Unknown Source)
at java.net.URLClassLoader.defineClass(Unknown Source)
at java.net.URLClassLoader.access$000(Unknown Source)
at java.net.URLClassLoader$1.run(Unknown Source)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(Unknown Source)
at java.lang.ClassLoader.loadClass(Unknown Source)
at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source)
at java.lang.ClassLoader.loadClass(Unknown Source)
at org.jasypt.util.text.BasicTextEncryptor.<init>(BasicTextEncryptor.java:67)
at eMain.<clinit>(eMain.java:4)
Caused by: java.lang.ClassNotFoundException: org.apache.commons.lang.exception.NestableRuntimeException
at java.net.URLClassLoader$1.run(Unknown Source)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(Unknown Source)
at java.lang.ClassLoader.loadClass(Unknown Source)
at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source)
at java.lang.ClassLoader.loadClass(Unknown Source)
... 14 more