22

我正在尝试从 Android 拨打电话，并且我也设置了运行时权限。它会询问是否允许打电话。但是当我按下允许时，应用程序崩溃：

这就是我实现它的方式：

private static final int REQUEST_PHONE_CALL = 1;
Intent intent = new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + "+918511812660"));

if (android.os.Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
    if (ContextCompat.checkSelfPermission(MainActivity.this, Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
        ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.CALL_PHONE},REQUEST_PHONE_CALL);
    }
    else
    {
        startActivity(intent);
    }
}
else
{
    startActivity(intent);
}



@Override
public void onRequestPermissionsResult(int requestCode,
                                       String permissions[], int[] grantResults) {
    switch (requestCode) {
        case REQUEST_PHONE_CALL: {
            if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                startActivity(intent);
            }
            else
            {

            }
            return;
        }
    }
}

这是我在 logcat 中获得的：

java.lang.RuntimeException: Failure delivering result ResultInfo{who=@android:requestPermissions:, 
     request=1, result=-1, data=Intent { act=android.content.pm.action.REQUEST_PERMISSIONS (has extras) }} 
     to activity {com.devpost.airway/com.devpost.airway.activities.MainActivity}: 
     java.lang.NullPointerException: Attempt to invoke virtual method 
     'java.lang.String android.content.Intent.toString()' on a null object reference

      at android.app.ActivityThread.deliverResults(ActivityThread.java:3733)
      at android.app.ActivityThread.handleSendResult(ActivityThread.java:3776)
      at android.app.ActivityThread.-wrap16(ActivityThread.java)
      at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1412)
      at android.os.Handler.dispatchMessage(Handler.java:102)
      at android.os.Looper.loop(Looper.java:148)
      at android.app.ActivityThread.main(ActivityThread.java:5461)
      at java.lang.reflect.Method.invoke(Native Method)
      at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726)
      at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)

Caused by: java.lang.NullPointerException: Attempt to invoke virtual method 
    'java.lang.String android.content.Intent.toString()' on a null object reference
      at android.app.Instrumentation.execStartActivity(Instrumentation.java:1485)
      at android.app.Activity.startActivityForResult(Activity.java:3930)
      at android.support.v4.app.BaseFragmentActivityJB.startActivityForResult(BaseFragmentActivityJB.java:48)
      at android.support.v4.app.FragmentActivity.startActivityForResult(FragmentActivity.java:75)
      at android.app.Activity.startActivityForResult(Activity.java:3890)
      at android.support.v4.app.FragmentActivity.startActivityForResult(FragmentActivity.java:856)
      at android.app.Activity.startActivity(Activity.java:4213)
      at android.app.Activity.startActivity(Activity.java:4181)
      at com.devpost.airway.activities.MainActivity.onRequestPermissionsResult(MainActivity.java:140)
      at android.app.Activity.dispatchRequestPermissionsResult(Activity.java:6582)
      at android.app.Activity.dispatchActivityResult(Activity.java:6460)
      at android.app.ActivityThread.deliverResults(ActivityThread.java:3729)
      at android.app.ActivityThread.handleSendResult(ActivityThread.java:3776) 
      at android.app.ActivityThread.-wrap16(ActivityThread.java) 
      at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1412) 
      at android.os.Handler.dispatchMessage(Handler.java:102) 
      at android.os.Looper.loop(Looper.java:148) 
      at android.app.ActivityThread.main(ActivityThread.java:5461) 
      at java.lang.reflect.Method.invoke(Native Method) 
      at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:726) 
      at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:616)

这可能是什么原因造成的？

4

7 回答 7

39

我建议在构造 Intent 呼叫特定号码时使用 ACTION_DIAL 而不是 ACTION_CALL 。使用 ACTION_DIAL ，您的应用程序将不需要呼叫权限，因为 ACTION_DIAL 会打开已输入号码的拨号器，并进一步允许用户决定是实际拨打电话还是在拨打电话之前修改电话号码或根本不拨打电话。

Intent intent = new Intent(Intent.ACTION_DIAL, Uri.parse("tel:" + "Your Phone_number"));// Initiates the Intent 
startActivity(intent);
于 2018-04-03T17:16:10.557 回答
29

堆栈跟踪似乎表明您的权限流程工作正常，但对startActivityfrom的调用onRequestPermissionsResult()正在崩溃。您Intent传递的startActivity设置是否正确？我看不到它在代码的那部分设置。

另请注意，它ContextCompat.checkSelfPermission代表您处理 SDK 版本检查，因此您应该能够使用

if (ContextCompat.checkSelfPermission(MainActivity.this, Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
    ActivityCompat.requestPermissions(MainActivity.this, new String[]{Manifest.permission.CALL_PHONE},REQUEST_PHONE_CALL);
}
else
{
    startActivity(intent);
}

本身，没有包装 SDK 版本检查代码。

于 2016-10-19T08:40:30.813 回答
6

你需要创建你Intent的onRequestPermissionsResult


@Override
public void onRequestPermissionsResult(int requestCode,
                                       String permissions[], int[] grantResults) {
    switch (requestCode) {
        case REQUEST_PHONE_CALL: {
            if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                    Intent intent = new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + "+918511812660"));
                startActivity(intent);
            }
            else
            {

            }
            return;
        }
    }
}
于 2016-10-19T08:47:18.607 回答
1

添加新方法

public static boolean hasPermissions(Context context, String... permissions) {
if (android.os.Build.VERSION.SDK_INT >= Build.VERSION_CODES.M && context != null && permissions != null) {
    for (String permission : permissions) {
        if (ActivityCompat.checkSelfPermission(context, permission) != PackageManager.PERMISSION_GRANTED) {
            return false;
        }
    }
}
return true;
}

在全球添加这个

int PERMISSION_ALL = 1; 
String[] PERMISSIONS = {Manifest.permission.READ_CONTACTS, Manifest.permission.CALL_PHONE};

并在 onCreate 中编写以下代码

if(!hasPermissions(this, PERMISSIONS)){
ActivityCompat.requestPermissions(this, PERMISSIONS, PERMISSION_ALL);
}
于 2016-10-19T08:29:39.957 回答
0 
 private void makePhoneCall() {
    String number = items;
    if (number.trim().length() > 0) {
        if (ContextCompat.checkSelfPermission(MainActivity.this,
                Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
            ActivityCompat.requestPermissions(MainActivity.this,
                    new String[]{Manifest.permission.CALL_PHONE}, REQUEST_CALL);
        } else {
            String dial = "tel:" + number;
            startActivity(new Intent(Intent.ACTION_CALL, Uri.parse(dial)));
        }
    } else {
        Toast.makeText(MainActivity.this, "Enter Phone Number", Toast.LENGTH_SHORT).show();
    }
}
@Override
public void onRequestPermissionsResult(int requestCode, @NonNull String[] permissions, @NonNull int[] grantResults) {
    if (requestCode == REQUEST_CALL) {
        if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
            makePhoneCall();
        } else {
            Toast.makeText(this, "Permission DENIED", Toast.LENGTH_SHORT).show();
        }
    }
}
于 2020-09-06T13:37:29.703 回答
0

最好不要对该操作使用 phone_call 权限。Google Play 控制台会提醒您，您应该避免向用户请求不必要的许可。这是一个更好的方法：

/**
 * Make a phone call. Send to the phone app
 *
 * @param phoneNumber the phone number to call
 */
private fun performPhoneCall(phoneNumber: String) {
    val intent = Intent(Intent.ACTION_DIAL)
    intent.data = Uri.parse("tel:$phoneNumber")
    try {
        context.startActivity(intent)
    } catch (ex: Exception) {
        displayErrorMessage()
    }
}
于 2021-11-10T20:53:02.710 回答
0

将您的更改onRequestPermissionsResult为下面，您基本上需要创建第intent一个，然后在授予权限时调用它。那就是你做错了。

@Override
public void onRequestPermissionsResult(int requestCode,
                                       String permissions[], int[] grantResults) {
    switch (requestCode) {
        case REQUEST_PHONE_CALL : {
            // If request is cancelled, the result arrays are empty.
            if (grantResults.length > 0
                    && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                Intent intent = new Intent(Intent.ACTION_CALL, Uri.parse("tel:" + "+918511812660"));

                if (ActivityCompat.checkSelfPermission(this, Manifest.permission.CALL_PHONE) == PackageManager.PERMISSION_GRANTED) {
                    startActivity(intent);
                }
            }
        }
    }
}
于 2016-10-19T08:44:52.223 回答