android - 如何在各种 Android 设备上获取应用程序名称？

Question

我正在使用以下代码在 Android 中获取应用程序名称。例如在 Galaxy S4 上；如果电话在Home screen，并且下面的函数返回TouchWiz home. 但是，在注释 4 中，函数返回Google Home. 我们有没有办法维护应用程序名称或根据设备名称检测名称？目前，我将 保存Home screen在与设备名称相对应的列表中。但是，我认为它不会涵盖所有可能的情况。

public String getAppName() {
        String foregroundProcess = "";
        ActivityManager activityManager = (ActivityManager) getApplicationContext().getSystemService(ACTIVITY_SERVICE);
        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.LOLLIPOP) {                                
            UsageStatsManager mUsageStatsManager = (UsageStatsManager) getSystemService(USAGE_STATS_SERVICE);
            long time = System.currentTimeMillis();
            List<UsageStats> stats = mUsageStatsManager.queryUsageStats(UsageStatsManager.INTERVAL_DAILY, time - 1000 * 1000, time); 
            // Sort the stats by the last time used
            if (stats != null) {
                SortedMap<Long, UsageStats> mySortedMap = new TreeMap<Long, UsageStats>();
                for (UsageStats usageStats : stats) {
                    mySortedMap.put(usageStats.getLastTimeUsed(), usageStats);
                }
                if (mySortedMap != null && !mySortedMap.isEmpty()) {
                    String topPackageName = mySortedMap.get(mySortedMap.lastKey()).getPackageName();
                    foregroundProcess = topPackageName;
                }
            }
        } else {                                                                                    
            @SuppressWarnings("deprecation")
            ActivityManager.RunningTaskInfo foregroundTaskInfo = activityManager.getRunningTasks(1).get(0);
            foregroundProcess = foregroundTaskInfo.topActivity.getPackageName();
        }

        //Convert package name to application name
        final PackageManager pm = getApplicationContext().getPackageManager();
        ApplicationInfo ai;
        try {
            ai = pm.getApplicationInfo(foregroundProcess, 0);
        } catch (final PackageManager.NameNotFoundException e) {
            ai = null;
        }
        String applicationName = (String) (ai != null ? pm.getApplicationLabel(ai) : "(unknown)");       

        return applicationName;
    }