我是easyadmin包的新手，我正在寻找是否可以直接从父对象添加子对象所以我得到了3个对象：-食谱
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Recipe
*
* @ORM\Table(name="recipe")
* @ORM\Entity(repositoryClass="AppBundle\Repository\RecipeRepository")
*/
class Recipe
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="name", type="string", length=100, nullable=true)
*/
private $name;
/**
* @var \DateTime
*
* @ORM\Column(name="createdon", type="datetime", nullable=true)
*/
private $createdon;
/**
* @var string
*
* @ORM\Column(name="description", type="text", nullable=true)
*/
private $description;
/**
* @var string
*
* @ORM\Column(name="version", type="string", length=5, nullable=true)
*/
private $version;
/**
* @ORM\OneToMany(targetEntity="Recipe_Product", mappedBy="recipe")
*/
private $recipeproducts;
...
-Recipe_Product（具有数量和单位作为要输入的属性）
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Recipe_Product
*
* @ORM\Table(name="recipe__product")
* @ORM\Entity(repositoryClass="AppBundle\Repository\Recipe_ProductRepository")
*/
class Recipe_Product
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="quantity", type="decimal", precision=10, scale=2, nullable=true)
*/
private $quantity;
/**
* @ORM\ManyToOne(targetEntity="Recipe", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="recipeid", referencedColumnName="id")
* })
*/
private $recipe;
/**
* @ORM\ManyToOne(targetEntity="Product", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="Productid", referencedColumnName="id")
* })
*/
private $product;
/**
* @ORM\ManyToOne(targetEntity="Unit", inversedBy="recipeproducts")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="Unitid", referencedColumnName="id")
* })
*/
private $unit;
...
当然还有一个 - 产品。
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* Product
*
* @ORM\Table(name="product")
* @ORM\Entity(repositoryClass="AppBundle\Repository\ProductRepository")
*/
class Product
{
/**
* @var int
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @ORM\Column(name="name", type="string", length=255)
*/
private $name;
/**
* @var string
*
* @ORM\Column(name="ref", type="string", length=25)
*/
private $ref;
/**
* @var string
*
* @ORM\Column(name="ref4stat", type="string", length=25)
*/
private $ref4Stat;
/**
* @var int
*
* @ORM\Column(name="size", type="integer")
*/
private $size;
/**
* @ORM\ManyToOne(targetEntity="Unit", inversedBy="products")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="unitid", referencedColumnName="id")
* })
*/
private $unit;
/**
* @ORM\ManyToOne(targetEntity="ProductType", inversedBy="products")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="producttypeid", referencedColumnName="id")
* })
*/
private $producttype;
/**
* @ORM\OneToMany(targetEntity="Recipe_Product", mappedBy="product")
*/
private $recipeproducts;
...
编辑食谱时，我希望能够直接添加一个新的 recipe_product 线，但我还没有找到一种方法来做到这一点......
有人有想法吗？
添加于 14/10：我找到了一种呈现表单的方法...在我的 easyadmin 配置文件中，我创建了以下条目：
Recipe:
class: AppBundle\Entity\Recipe
form:
fields:
- name
- beer
- version
- description
- createdon
- { property: 'recipeproducts', label: 'Ingredients', type: 'collection', type_options: {entry_type: 'AppBundle\Form\Recipe_ProductType', by_reference: false} }
表单代码为
<?php
namespace AppBundle\Form;
use Symfony\Component\Form\AbstractType;
use Symfony\Component\Form\FormBuilderInterface;
use Symfony\Component\OptionsResolver\OptionsResolver;
use Symfony\Component\Form\Extension\Core\Type\HiddenType;
class Recipe_ProductType extends AbstractType
{
/**
* @param FormBuilderInterface $builder
* @param array $options
*/
public function buildForm(FormBuilderInterface $builder, array $options)
{
$builder
->add('product')
->add('quantity')
->add('unit')
;
}
/**
* @param OptionsResolver $resolver
*/
public function configureOptions(OptionsResolver $resolver)
{
$resolver->setDefaults(array(
'data_class' => 'AppBundle\Entity\Recipe_Product'
));
}
}
呈现表单（不创建两个实体之间的链接，但我猜它必须在管理控制器中）