1

嗨，我想用 - 和 ; 和：在sql server中并插入到另一个表中

declare @data varchar(max)=null
set @data='nt:865067021846160;2;8.5.05;1,1,20161010102239.000,18.580423,73.815948,549.700,0.28,33.6,11;101;100;0;0;0;FF;146;25}'


col1     col2           col3     col4
Nt  895067021846160     2       7.5.05
nt  875067021846160     3      8.5.05
nt  835067021846160     5      8.5.05

很快

我使用了 substring 和 CHARINDEX 但我没有得到正确的结果。谢谢

4

2 回答 2

1

有许多可用于字符串拆分要求的解决方案，您可以从此处使用其中一种字符串拆分功能fnSplitString

我只是演示如何在您的情况下使用此功能。

尝试全部转换-，;使用:

declare @data varchar(max)=null
set @data='nt:865067021846160;2;8.5.05;1,1,20161010102239.000,18.580423,73.815948,549.700,0.28,33.6,11;101;100;0;0;0;FF;146;25}'
SET @data=REPLACE(REPLACE(@data,'-',':'),';',':')

现在fnSplitString如下调用它，这将给出包含所有字符串片段的单列表。

INSERT INTO #TableName(Col1) SELECT * FROM dbo.fnSplitString(@data,':')

这将给出这样的输出

nt
865067021846160
2
8.5.05
1,1,20161010102239.000,18.580423,73.815948,549.700,0.28,33.6,11
101
100
0
0
0
FF
146
25}
于 2016-10-12T07:29:03.937 回答
1

试试下面的脚本。

DECLARE @data VARCHAR(Max) = 'nt:865067021846160;2;8.5.05;1,1,20161010102239.000,18.580423,73.815948,549.700,0.28,33.6,11;101;100;0;0;0;FF;146;25}'
DECLARE @SpitChars varchar(100) = '%[:;-]%'

;WITH cte_1 
  AS
    (
        SELECT PATINDEX(@SpitChars, @data) - 1 + case when  PATINDEX(@SpitChars, Left(@data,1)) = 1 then 1 else 0 end AS LineBreaker
            , @data AS dataString
            ,SUBSTRING(@data, 1, ISNULL(NULLIF(PATINDEX(@SpitChars, @data), 0) - 1 +case when  PATINDEX(@SpitChars, Left(@data,1)) = 1 then 1 else 0 end, 8000)) AS [Extract]
        UNION ALL
        SELECT LineBreaker + ISNULL(NULLIF(PATINDEX(@SpitChars, SUBSTRING(dataString, LineBreaker+1 , 8000)), 0) -  case when  PATINDEX(@SpitChars, SUBSTRING(dataString, LineBreaker+1 , 8000)) = 1 then 0 else 1 end  ,datalength(dataString)-LineBreaker) LineBreaker
            , dataString
            ,SUBSTRING(dataString, LineBreaker+ 1 , ISNULL(NULLIF(PATINDEX(@SpitChars, SUBSTRING(dataString, LineBreaker+1 , 8000)), 0) -  case when  PATINDEX(@SpitChars, SUBSTRING(dataString, LineBreaker+1 , 8000)) = 1 then 0 else 1 end  ,datalength(dataString)-LineBreaker)) AS [Extract]
        FROM  cte_1
        WHERE LineBreaker BETWEEN 1 AND datalength(@data)-1 
    )
SELECT [1] Col1,[2] Col2,[3] Col3,[4] Col4,[5] Col5
      ,[6] Col6,[7] Col7,[8] Col8,[9] Col9,[10] Col10
      ,[11] Col11,[12] Col12,[13] Col13
FROM(
SELECT [Extract],ROW_NUMBER()OVER( ORDER BY (SELECT 1))RNO
FROM  cte_1
WHERE [Extract] NOT IN (':',';','-'))t
PIVOT(MAX([Extract]) FOR [RNO] IN ([1],[2],[3],[4],[5],[6],[7],[8],[9],[10],[11],[12],[13]) )as pvt
于 2016-10-12T07:33:05.393 回答