sql - 使用 DENSE_RANK 排除空值

Question

Dense_Rank 考虑了一切。有没有办法排除空值，所以 1 之后的下一个排名将是 2 而不是 3。

这是表格现在的样子：

 A     | DENSE_R 
 --------------
 1     | 1  
 --------------
 2     | null  
 --------------
 3     | 3 
 --------------
 4     |  4    

这就是我希望表格的样子：

 A     | DENSE_R 
 --------------
 1     | 1  
 --------------
 2     | null  
 --------------
 3     | 2 
 --------------
 4     |  3  

我正在使用以下代码来执行此操作：-

WITH CTE AS
(
 SELECT A 
 FROM A1
)
SELECT A,
CASE 
  WHEN  **Condition**
  THEN DENSE_RANK() OVER (Order by [A] ASC)
END
AS 'DENSE_R'
FROM CTE

Answer 1

使用与您已经使用partition by的相同的方法。**Condition**

WITH CTE AS
(
 SELECT A 
 FROM A1
)
SELECT A,
CASE 
  WHEN  **Condition**
  THEN DENSE_RANK() OVER (Partition by (case when **Condition** then 1 else 0 end) Order by [A] ASC)
END
AS 'DENSE_R'
FROM CTE

Answer 2

你可以case这样使用：

select A,
       (case when A is not null
             then dense_rank() over (partition by (case when A is not null then 1 else 0 end)
                                     order by a desc
                                    )
        end) as dr
from A1;