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我正在尝试打印定义为 LpVariable（PuLP 1.6.1，Python 3.5）的变量的值。LpVariable 具有将参数类别设置为“整数”的选项。但是，当我要求打印变量时，这不会产生值。特此我要解决的一个问题：

from pulp import *

prob = LpProblem("Gadget Production", LpMinimize)

# Demand scheme x (Laptops), y (Phones), and z (Tablets)
x = [75, 125, 1000, 1500]
y = [120, 2000, 2000, 2000]
z = [50, 2000, 3000, 2000]

PL1 = LpVariable('Prod Laptop January', cat=int)
PL2 = LpVariable('Prod Laptop February', cat=int)
PL3 = LpVariable('Prod Laptop March', cat=int)

PP1 = LpVariable('Prod Phone January', cat=int)
PP2 = LpVariable('Prod Phone February', cat=int)
PP3 = LpVariable('Prod Phone March', cat=int)

PT1 = LpVariable('Prod Tablet January', cat=int)
PT2 = LpVariable('Prod Tablet February', cat=int)
PT3 = LpVariable('Prod Tablet March', cat=int)

# Inventory (I) of gadget (L, P, T), in month [i]:
IL1 = x[0] + PL1 - x[1]
IL2 = IL1 + PL2 - x[2]
IL3 = IL2 + PL3 - x[3]

IP1 = y[0] + PP1 - y[1]
IP2 = IP1 + PP2 - y[2]
IP3 = IP2 + PP3 - y[3]

IT1 = z[0] + PT1 - z[1]
IT2 = IT1 + PT2 - z[2]
IT3 = IT2 + PT3 - z[3]

# Constraints to meet demand scheme
prob += x[0] + PL1 >= x[1]
prob += IL1 + PL2 >= x[2]
prob += IL2 + PL3 >= x[3]

prob += y[0] + PP1 >= y[1]
prob += IP1 + PP2 >= y[2]
prob += IP2 + PP3 >= y[3]

prob += z[0] + PT1 >= z[1]
prob += IT1 + PT2 >= z[2]
prob += IT2 + PT3 >= z[3]

# Constraints to meet maximal production hours
prob += 5*PL1 + 2*PP1 + 4*PT1 <= 23000
prob += 5*PL2 + 2*PP2 + 4*PT2 <= 23000
prob += 5*PL3 + 2*PP3 + 4*PT3 <= 23000

# Overtime costs, function to be minimized
OT1 = (5*PL1 + 2*PP1 + 4*PT1) - 20000
OT2 = (5*PL2 + 2*PP2 + 4*PT2) - 20000
OT3 = (5*PL3 + 2*PP3 + 4*PT3) - 20000

prob += IL1 + IL2 + IL3 + IP1 + IP2 + IP3 + IT1 + IT2 + IT3 + 10 * (OT1 + OT2 + OT3)

# Solve the problem
prob.solve()

# print solve status
print("Status:", LpStatus[prob.status])

# Print optimum values
for v in prob.variables():
    print(v.name, "=", v.varValue)

print("Total Costs = ", value(prob.objective))
print(OT1)

这给了我以下结果：

Status: Optimal
Prod_Laptop_February = 1000.0
Prod_Laptop_January = 50.0
Prod_Laptop_March = 1500.0
Prod_Phone_February = 2000.0
Prod_Phone_January = 1880.0
Prod_Phone_March = 2000.0
Prod_Tablet_February = 3000.0
Prod_Tablet_January = 1950.0
Prod_Tablet_March = 2000.0
Total Costs =  -76900.0
5*Prod_Laptop_January + 2*Prod_Phone_January + 4*Prod_Tablet_January - 20000

我希望最后一行是一个整数值，但事实并非如此。有人可以向我解释如何将表达式转换为整数值吗？

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代码中的最后一个打印状态将打印一个纸浆表达式。由于它是一个非本地 python 对象，它的字符串表示由 PuLP（类内重载）定义。

在这种情况下，表达式本身以人类可读的形式呈现。

如果要访问它的值，只需将最后一行替换为：

print(OT1.value())
于 2016-10-11T11:10:10.990 回答