我有一个使用我拥有的 WSDL 生成的客户端。当我尝试连接到此 WebService 时,出现以下错误:
javax.xml.ws.soap.SOAPFaultException: An error occurred when verifying security for the message.
at org.apache.cxf.jaxws.JaxWsClientProxy.invoke(JaxWsClientProxy.java:161)
托管 WebService 的实际服务器需要一个包含安全标头的 SOAP 消息,例如:
<soapenv:Header>
<o:Security s:mustUnderstand="1" xmlns:o="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd">
<o:UsernameToken u:Id="XXXX">
<o:Username>XXXX</o:Username>
<o:Password Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText">XXXX</o:Password>
</o:UsernameToken>
</o:Security>
</soapenv:Header>
如何将其与发出请求时生成的 SOAP 消息一起获取?这就是我在代码中调用 WebService 的方法:
val factory = new org.apache.cxf.jaxws.JaxWsProxyFactoryBean()
factory.setServiceClass(classOf[MyWebService])
// if there is an address, then let's set it!
factory.setAddress("https://my/server/address/MyWebService.svc")
// log incoming and outgoing
factory.getInInterceptors.add(new org.apache.cxf.interceptor.LoggingInInterceptor())
factory.getOutInterceptors.add(new org.apache.cxf.interceptor.LoggingOutInterceptor())
val myServiceClient = factory.create().asInstanceOf[MyWebService]
myServiceClient.myMethod("param")
有什么建议么?